First Steps in Geometry: A Series of Hints for the Solution of Geometrical Problems with Notes on Euclid, Useful Working Propositions and Many ExamplesLongmans, Green, and Company, 1887 - 180 sider |
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Resultat 1-5 av 23
Side 3
... established by Euclid , nor obviously deducible ( that is , deducible as corollaries ) from his propositions . Hence these properties may themselves be presented as exercises on Euclid - and in fact most of them will be found in ...
... established by Euclid , nor obviously deducible ( that is , deducible as corollaries ) from his propositions . Hence these properties may themselves be presented as exercises on Euclid - and in fact most of them will be found in ...
Side 8
... established which seems to promise to be useful towards the solution of a problem , to re - draw the figure , omitting all lines except those which have served to guide you to this result . But , except in such instances , or where the ...
... established which seems to promise to be useful towards the solution of a problem , to re - draw the figure , omitting all lines except those which have served to guide you to this result . But , except in such instances , or where the ...
Side 10
... establish the identity of two ex- pressions . In such cases we may either take one expression , and try to work it into the same form as the other , or vice versa , we may select the latter to work upon , or — which is the surer process ...
... establish the identity of two ex- pressions . In such cases we may either take one expression , and try to work it into the same form as the other , or vice versa , we may select the latter to work upon , or — which is the surer process ...
Side 11
... established . For we proceed from the data - A C , CE , equal to BE , CE , and the included angles equal -to the equality of the triangles ACE , BCE in all respects , and thence to the equality of A E , EB . In the analytical solution ...
... established . For we proceed from the data - A C , CE , equal to BE , CE , and the included angles equal -to the equality of the triangles ACE , BCE in all respects , and thence to the equality of A E , EB . In the analytical solution ...
Side 13
... establish the equality of the angles HA B , HAC . Can we , then , prove the equality of the sides HB , HC ? This would involve the equality of the angles HBC , HCB ( Euc . I. , 6 ) ; and this is one of our data . Hence we see our way at ...
... establish the equality of the angles HA B , HAC . Can we , then , prove the equality of the sides HB , HC ? This would involve the equality of the angles HBC , HCB ( Euc . I. , 6 ) ; and this is one of our data . Hence we see our way at ...
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First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Ingen forhåndsvisning tilgjengelig - 2013 |
Vanlige uttrykk og setninger
A B C D A B is equal ABCD angle ABC angle BA angle equal base bisector bisects the angle circle diagonals divided equal and parallel equal angles equal sides equal to DC equal to half equal to twice Euclid exterior angles given angle given line given point given straight line greater Hence hypotenuse intersect isosceles triangle KHGE lines bisecting lines drawn locus maxima and minima obtuse opposite sides parallelogram perpendicular point F problem produced proof Prop proposition quadrilateral R. A. PROCTOR rect rectangle A C rectangle contained respects Euc rhombus right angles right-angled triangle sides A B solution square on CD squares on A C straight line A B theorems trapezium triangle ABC trisected twice the rectangle vertex vertical angle
Populære avsnitt
Side 80 - If two triangles have two sides of the one equal to two sides of the...
Side 144 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Side 175 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Side 136 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.