First Steps in Geometry: A Series of Hints for the Solution of Geometrical Problems with Notes on Euclid, Useful Working Propositions and Many ExamplesLongmans, Green, and Company, 1887 - 180 sider |
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Resultat 1-5 av 24
Side 7
... shown in Fig . 4 ; here the angle A is one of about 75 ° , the angle B one of about 60 ° , and the angle C one of about 45 ° . When a quad- rilateral figure is not necessarily either a parallelogram or a trapezium , it is well to ...
... shown in Fig . 4 ; here the angle A is one of about 75 ° , the angle B one of about 60 ° , and the angle C one of about 45 ° . When a quad- rilateral figure is not necessarily either a parallelogram or a trapezium , it is well to ...
Side 20
... shown that CF is at right angles to BC , and therefore , of course , CF is at right angles to AD . It will be as well , therefore , to produce A D to meet FC in H , and to note that A H is at right angles to FC . But CAF is an isosceles ...
... shown that CF is at right angles to BC , and therefore , of course , CF is at right angles to AD . It will be as well , therefore , to produce A D to meet FC in H , and to note that A H is at right angles to FC . But CAF is an isosceles ...
Side 37
... shown to be possible . Therefore , the following proof of the first part of the proposition would not be in his manner , though it would be difficult to find any flaw in the reasoning . There must be some line which divides BAC ( Fig ...
... shown to be possible . Therefore , the following proof of the first part of the proposition would not be in his manner , though it would be difficult to find any flaw in the reasoning . There must be some line which divides BAC ( Fig ...
Side 43
... shown that the triangle increases as the angle at B increases . We are led , therefore , at once to the consideration that our triangle will have its greatest area when the angles at A and B are equal . To see whether this is the case ...
... shown that the triangle increases as the angle at B increases . We are led , therefore , at once to the consideration that our triangle will have its greatest area when the angles at A and B are equal . To see whether this is the case ...
Side 44
... the work in that example . We find that AL and LB are together greater than A E , so that H does fall below L ; and the triangle AKB is greater than the triangle AH B. Our surmise is , therefore , shown to 44 GEOMETRICAL PROBLEMS .
... the work in that example . We find that AL and LB are together greater than A E , so that H does fall below L ; and the triangle AKB is greater than the triangle AH B. Our surmise is , therefore , shown to 44 GEOMETRICAL PROBLEMS .
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First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Ingen forhåndsvisning tilgjengelig - 2013 |
Vanlige uttrykk og setninger
A B C D A B is equal ABCD angle ABC angle BA angle equal base bisector bisects the angle circle diagonals equal and parallel equal angles equal sides equal to DC equal to half equal to twice Euclid exterior angles given angle given line given point given straight line greater Hence hypotenuse intersect isosceles triangle KHGE lines bisecting lines drawn locus maxima and minima obtuse opposite sides parallelogram perpendicular point F problem produced proof Prop proposition quadrilateral R. A. PROCTOR rect rectangle A C rectangle contained respects Euc rhombus right angles right-angled triangle sides A B solution square on CD squares on A C straight line A B theorems trapezium triangle ABC twice the rectangle vertex vertical angle
Populære avsnitt
Side 80 - If two triangles have two sides of the one equal to two sides of the...
Side 144 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Side 175 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Side 136 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.