 | Adrien Marie Legendre - 1819 - 574 sider
...proportional sought. For the perpendicular GE, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DE, EF (215), and these two segments are equal to the two given lines A and B. PHOBLEM. 240. To divide... | |
 | Adrien Marie Legendre - 1825 - 276 sider
...proportional sought. For the perpendicular GE, let fall from the point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DE, EF (Wb), and these two segments are equal to the two given lines A and B. PROBLEM. 240. To divide... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 sider
...proportional sought. For the perpendicular GE, let fall from the point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DE, EF (21 5), and these two segments are equal to the two given lines A and B. PROBLEM. 240. To divide... | |
 | James Hayward - 1829 - 228 sider
...truths just proved ; (1). A perpendicular drawn from any point in the circumference of a circle to the diameter, is a mean proportional between the two segments of the diameter; (2). If, from the vertex of an angle inscribed in a semicircle a perpendicular be drawn to the diameter,... | |
 | Adrien Marie Legendre - 1841 - 288 sider
...proportional sought. For the perpendicular GE, let fall from the point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DE, EF (215), and these two segments are equal to the two given lines A and B. PROBLEM. 240. To divide... | |
 | Adrien Marie Legendre - 1852 - 436 sider
...proportional required. For, the perpendicular EG,* let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DEj EF (p. 23, C.) ; and these segments are equal to the given lines A and B, PROBLEM IV. To divide... | |
 | Charles Davies - 1854 - 436 sider
...proportional required. For, the perpendicular EG, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DS, EF (p. 23, c.) ; and these segments are equal to the given lines A and B, PROBLEM IV. To divide... | |
 | George Roberts Perkins - 1856 - 460 sider
...diameter, is called an ordinate to this diameter. Hence, we have this condition : In a circle any ordinate to a diameter is a mean proportional between the two segments of this diameter. We can show that this property is one of the consequences of the properties of right-angled... | |
 | Adrien Marie Legendre, Charles Davies - 1857 - 442 sider
...proportional required. For, the perpendicular EG, let fall from a point in the circumfereoce upon the diameter, is a mean proportional between the two segments of the diameter DE, EF (p. 23, C.) ; and these segments are equal to the given lines A and B, PROBLEM IV. To divide... | |
 | Elias Loomis - 1857 - 242 sider
...proportional required. For the perpendicular BD, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter AB, BC (Prop. XXII., Cor., B. IV.) ; and these segments are equal to the wo given lines. PROBLEM XX.... | |
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EG, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DS, EF (p. 
