Examples in PhysicsMacmillan and Company, 1888 - 260 sider |
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Side 23
... inch = 2.54 cm . I pound = 453.6 gm . 1. State and discuss Newton's First Law of Motion , and show that it provides us with a definition of force . 2. Enunciate Newton's Second Law ; state the exact meaning of the phrase " change of ...
... inch = 2.54 cm . I pound = 453.6 gm . 1. State and discuss Newton's First Law of Motion , and show that it provides us with a definition of force . 2. Enunciate Newton's Second Law ; state the exact meaning of the phrase " change of ...
Side 30
... inches , and what is the length of a pendulum which loses 10 minutes a day at this place ? 67. The bob of a pendulum can be raised by means of a screw which has thirty threads to the inch ; if the pendulum loses 5 minutes a day , how ...
... inches , and what is the length of a pendulum which loses 10 minutes a day at this place ? 67. The bob of a pendulum can be raised by means of a screw which has thirty threads to the inch ; if the pendulum loses 5 minutes a day , how ...
Side 35
... inches , and the piston moves through a distance of 10 inches find the work done per stroke , assuming the pressure of the steam in the cylinder to be constant and equal to 30 lbs . per square inch . 90. Two bodies of 80 lbs . and 60 ...
... inches , and the piston moves through a distance of 10 inches find the work done per stroke , assuming the pressure of the steam in the cylinder to be constant and equal to 30 lbs . per square inch . 90. Two bodies of 80 lbs . and 60 ...
Side 39
... inches high fourteen times . Show that the energy thus spent would suffice to stop a thief weighing 13 stones and running at the rate of 10 miles an hour . = 13 st . 189 lbs . , and 10 miles an hour = 44/3 feet per second . Thus the ...
... inches high fourteen times . Show that the energy thus spent would suffice to stop a thief weighing 13 stones and running at the rate of 10 miles an hour . = 13 st . 189 lbs . , and 10 miles an hour = 44/3 feet per second . Thus the ...
Side 43
... inches . P = pressure upon the piston in pounds per square inch . S = length of stroke in feet . R = number of revolutions per minute . Here P denotes the intensity of the pressure on the piston in pounds weight per square inch . The ...
... inches . P = pressure upon the piston in pounds per square inch . S = length of stroke in feet . R = number of revolutions per minute . Here P denotes the intensity of the pressure on the piston in pounds weight per square inch . The ...
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acceleration amount of heat ampère Assistant Master atmospheric pressure barometer barometric height battery body of mass C.G.S. units Calculate calorimeter Camb Cambridge cells charge circuit coefficient of expansion College column constant containing copper cubic centimetres cubic foot cylindrical deflection denote density diameter distance dynes electricity electromotive force ELEMENTARY equal equation ergs expressed Fcap feet per second find the specific focal length foot-pounds galvanometer glass grammes GREEK heat-units horse-power Illustrated immersed internal resistance iron kilogramme kinetic energy latent heat lens liquid litre logarithm magnetic Matric measure melted mercury metres per second miles mirror mixture ohms pendulum piston placed pole potential poundals pounds pounds weight produced Prof Professor prove radius revised School specific gravity specific heat sphere square centimetre square inch steam string surface temperature tube unit of length velocity vertical vessel volume weight per square wire
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