An Introduction to Algebra: With Notes and Observations : Designed for the Use of Schools and Places of Public Education : to which is Added an Appendix on the Application of Algebra to GeometryEvert Duyckinck, Daniel D. Smith and George Long, 1818 - 260 sider |
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Resultat 1-5 av 21
Side 54
... Resolve the given number , or quantity , into two fac- tors , one of which shall be the greatest power contained in it , and set the root of this power before the remaining part , with the proper radical sign between them . ( r ) ...
... Resolve the given number , or quantity , into two fac- tors , one of which shall be the greatest power contained in it , and set the root of this power before the remaining part , with the proper radical sign between them . ( r ) ...
Side 94
... resolved as before . EXAMPLES . ~ 1 . Given { 3x + 5y = 40 and y . to find the values of x First , multiply the second equation by 3 , and it will give 3x + 6y = 42 . Then , subtract the first equation from this , and it will give 6y5y ...
... resolved as before . EXAMPLES . ~ 1 . Given { 3x + 5y = 40 and y . to find the values of x First , multiply the second equation by 3 , and it will give 3x + 6y = 42 . Then , subtract the first equation from this , and it will give 6y5y ...
Side 96
... equations , which may be resolved by the former rules . And in nearly the same way may four , five , & c . un- known quantities be exterminated from the same num- ber of independent simple equations ; but , in cases 96 SIMPLE EQUATIONS .
... equations , which may be resolved by the former rules . And in nearly the same way may four , five , & c . un- known quantities be exterminated from the same num- ber of independent simple equations ; but , in cases 96 SIMPLE EQUATIONS .
Side 109
... resolved by means of the following rule : RULE . Transpose all the terms that involve the unknown quantity to one side of the equation , and the known terms to the other ; observing to arrange them so , that the term which contains the ...
... resolved by means of the following rule : RULE . Transpose all the terms that involve the unknown quantity to one side of the equation , and the known terms to the other ; observing to arrange them so , that the term which contains the ...
Side 110
... resolved like quadratics , by first finding the value of the square root of the first term , according to the method used in the above rule , and then taking such a root , or power of the result , as is denoted by the re- duced index of ...
... resolved like quadratics , by first finding the value of the square root of the first term , according to the method used in the above rule , and then taking such a root , or power of the result , as is denoted by the re- duced index of ...
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Vanlige uttrykk og setninger
Algebra arise arithmetical mean arithmetical series bers coefficient common index consequently cube root cubic equation decimal denoted determine divisor equal EXAMPLES FOR PRACTICE find the difference find the square find the sum find the value find two numbers frac fraction geometrical progression geometrical series give given equation given number greatest common measure Hence infinite series last term letters loga logarithms multiplied natural number negative nth root number of terms number required orders of differences perpendicular plane triangle PROBLEM proportion quadratic equation question quotient rational remainder required the numbers Required the product Required the sum required to convert required to divide required to find required to reduce result right angled triangle rithm rule second term simple form square number square root substituted subtracted surd tion transposition triangle ABC unknown quantity Whence whole numbers α α
Populære avsnitt
Side 37 - Now .} of f- is a compound fraction, whose value is found by multiplying the numerators together for a new numerator, and the denominators for a new denominator.
Side 20 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Side 40 - ... required. Or, multiply the quantity into itself as many times, less one, as is denoted by the index of the power, and the last product will be tJie answer.
Side 201 - From which it is evident, that the logarithm of the product of any number of factors is equal to the sum of the logarithms of those factors.
Side 107 - A hare is 50 leaps before a greyhound, and takes 4 leaps to the greyhound's 3 ; but 2 of the greyhound's leaps are equal to 3 of the hare's ; how many leaps must the greyhound take, to catch the hare ? Let x be the number of leaps taken by the hound.
Side 121 - It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14.
Side 107 - To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied...
Side 108 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Side 121 - It is required to divide the number 60 into two such parts, that their product shall be to the sum of their squares in the ratio of 2 to 5.
Side 31 - To reduce an improper fraction to a whole or mixed quantity. RULE. Divide the numerator by the denominator, for the integral part, and place the remainder, if any, over the denominator, for the fractional part; then the two, joined together, with the proper sign between them, will give the mixed quantity required.