 | 1801 - 446 sider
...#-f-4~y/25d:^z: 16 by evolution ; And therefore #— 16 — 4=12= less number, and 12-jS z:2o=r greater. ' 2. To divide the number 60 into two such parts, that their product may be 864. Let X = greater part, Then Then will 60 — x= less, And wX6c — x'=6ox — #'—864 by... | |
 | John Bonnycastle - 1811 - 230 sider
...PRACTICE. 1 . What two numbers are those whose sirn is 20, and theix product 36? Ans. 2 and 18. 2. To divide the number 60 into two such parts, that their product may be to the sum of their squares in. the ratio of 2 to 5. Ans. 20 and 40. 3. The difference of two... | |
 | John Bonnycastle - 1813 - 456 sider
...rectangle of the whole and one of the parts shall be equal to the square of the other. Ans. 10/5 — 10 5. It is required to divide the number 60 into two...2 to 5. Ans. 20 and 40 6. It is required to divide 146 into two such parts, that the difference of their square roots may be 6. Ans. 25 and 121 7. What... | |
 | Jeremiah Day - 1820 - 352 sider
...and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their. product shall be to the sum of their squares, as 3 to 1 0. Ans. 1 8 and 6. 13. In a mixture of rum and brandy, the difference between the quantities... | |
 | Bewick Bridge - 1821 - 284 sider
...j/)'=72, Again, x*—2xу+у'=4, and 4xy =96. or ж+^=ю,| but x— y=2 ; Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. : ANSWER, 18 and 6. Ex. 7. There are two numbers which are to each other as 3 : 2. If 6... | |
 | Francis Tillett - 1824 - 94 sider
...6720-^-12= j ( oD 560=a:з/ ; we then have given ѕ=48, and p=560, to find 3? and y. Answer 20 and 28. 7. It is required to divide the number 60 into two such parts that the product of two-thirds of each of them shall be=384. First -Х-=ф then384x9=3456,and 3456-7-4=864;... | |
 | John Bonnycastle - 1825 - 336 sider
...common rule, before given, Therefore ar=16 — 4=12, the less number, and x+6 =12+8=20, the greater. 2. It is required to divide the number 60 into two such parts, that their product shall be 864. , Let x= th,e greater part, Then will 60— x = the less, And ar(60— z)-= 60x— z3= 864, by... | |
 | Peter Nicholson - 1825 - 1046 sider
...8 3. To divide the numoer 33 into two such parts that their product ihall be 162. Ans. 27 and 6. 4. To divide the number 60 into two such parts, that their product may be to the sum of their squares in the ratio of 2 to 5. Ans. 20 and 40. 5. The difference of two... | |
 | Warren Colburn - 1826 - 290 sider
...borrowing and spending as before ; after which he had nothing left. How much money had he at first ? 23. It is required to divide the number 60 into two such parts, that one seventh of the one may be equal to one eighth of the other. 42 Jllgebra. VII. 24. It is required... | |
 | Jeremiah Day - 1827 - 352 sider
...and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares, as 3 to 10. Ans. 18 and 6. 13. In a mixture of rum and brandy, the difference between the quantities... | |
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It is required to divide the number 60 into two such parts, that their product shall be to the sum of their squares in the ratio of 2 to 5. 
