 | William Nicholson - 1809 - 722 sider
...sqnare of its height ; multiply the sum by the height, and the product by .r>'236.' Or, 2<Uy, From three times the diameter of the sphere, subtract twice the height of the fribtnim ; multiply the remaintier by the square of the height, and the product by .5236. SEGUIERIA,... | |
 | Thomas Keith - 1817 - 306 sider
...is the .greatest. PROBLEM XIII. Tojlnd the Solidity of the Segment of a Sphere. RULE 1 *. From three times the diameter of the sphere, subtract twice the height of the segment ; multiply * Demonstrauon. Let A cm represent a triangular pyramid, whose tide m A is infinitely small. The sphere... | |
 | William Hawney - 1820 - 336 sider
...become d2+fAa ; xA.x .785* ix Ax. 7854. To find the Solidity of the Segment of a Sphere. From three times the diameter of the sphere subtract twice the height of the segment ; multiply the remainder by the square of the height, and that product by .5236, and the last product will be the... | |
 | William Nicholson - 1821 - 382 sider
...square of its height ; multiply the sum by the height, and the pioduct by .52J6. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIER1A,... | |
 | James Mitchell - 1823 - 666 sider
...square of its height; multiply the sum by the height, and the product by -5236. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum ; multiply the remainder by the square of the height, and the product by -5236. That is, in... | |
 | Anthony Nesbit - 1824 - 476 sider
...multiplied by the height, and the product again by .5236, will give the solidity. RULE II. From three times the diameter of the sphere subtract twice the height of the segment; multiply the remainder by the square of the height, and that pro-i duct by .5236 for the solidity, Note l. The surface... | |
 | John Bonnycastle - 1829 - 256 sider
...sum multiplied by the height, and the product again by .5236, will give the solidity. Or, From three times the diameter of the sphere subtract twice the height of the segment, multiply by the square of the height, and that .product by .5236 ; the last product will be the solidity. EXAMPLES.... | |
 | William Templeton (engineer.) - 1833 - 224 sider
...base is circular or parallel to the revolving axis. RULE. — From triple the fixed axis, take double the height of the segment ; multiply the difference by the square of the height, and by .5236 ; then say, as the square of the fixed axis is to the square of the revolving axis, so is the former... | |
 | J. M. Scribner - 1844 - 130 sider
...height of the segment be known, the solidity may be easily found by the following Rule. — From three times the diameter of the sphere, subtract twice the height of the segment ; then multiply the remainder by the square of the height and the product by the decimal .5236. Ex.... | |
 | Scottish school-book assoc - 1845 - 444 sider
...PROBLEM X. by the height, and the product again by -5236, will give the solidity. EULB II. From three times the diameter of the sphere subtract twice the height of the segment ; multiply the remainder by the square of the height and by -5236. NOTE. For the demonstration of the above Rules... | |
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From three times the diameter of the sphere subtract twice the height of the segment, multiply by the square of the height, and that product by .5236; the last product will be the solidity. 
