Plane and Solid GeometryGinn, 1913 - 470 sider |
Inni boken
Resultat 1-5 av 55
Side v
... CHORDS SECANTS AND TANGENTS LINE OF CENTERS MEASURE OF ANGLES PROBLEMS OF CONSTRUCTION SOLUTION OF PROBLEMS EXERCISES BOOK III . PROPORTION . SIMILAR POLYGONS . THEORY OF PROPORTION PROPORTIONAL LINES SIMILAR POLYGONS NUMERICAL ...
... CHORDS SECANTS AND TANGENTS LINE OF CENTERS MEASURE OF ANGLES PROBLEMS OF CONSTRUCTION SOLUTION OF PROBLEMS EXERCISES BOOK III . PROPORTION . SIMILAR POLYGONS . THEORY OF PROPORTION PROPORTIONAL LINES SIMILAR POLYGONS NUMERICAL ...
Side 95
... chord . A chord is said to subtend the arcs that it cuts from a circle . Unless the contrary is stated , the chord is taken as subtending the minor arc . ARC MINOR CHORD MAJOR 4RO PROPOSITION III . THEOREM 1 170. In the same circle ...
... chord . A chord is said to subtend the arcs that it cuts from a circle . Unless the contrary is stated , the chord is taken as subtending the minor arc . ARC MINOR CHORD MAJOR 4RO PROPOSITION III . THEOREM 1 170. In the same circle ...
Side 96
... chord . B Α ' Given two equal circles with centers O and O ' , with arcs AB and A'B ' equal , and with arc AF greater than arc A'B ' . To prove that 1. chord AB chord A'B ' ; = 2. chord AF > chord A'B ' . Proof . 1. Draw the radii OA ...
... chord . B Α ' Given two equal circles with centers O and O ' , with arcs AB and A'B ' equal , and with arc AF greater than arc A'B ' . To prove that 1. chord AB chord A'B ' ; = 2. chord AF > chord A'B ' . Proof . 1. Draw the radii OA ...
Side 97
... chords AB and A'B ' equal , and with chord AF greater than chord A'B ' . Το prove that 1. arc AB arc A'B ' ; 2. arc AF > arc A'B ' . Since Proof . 1. Draw the radii OA , OB , OF , O'A ' , O'B ' . and OA = O'A ' , and OB = 0'B ' , chord AB = ...
... chords AB and A'B ' equal , and with chord AF greater than chord A'B ' . Το prove that 1. arc AB arc A'B ' ; 2. arc AF > arc A'B ' . Since Proof . 1. Draw the radii OA , OB , OF , O'A ' , O'B ' . and OA = O'A ' , and OB = 0'B ' , chord AB = ...
Side 98
... chord bisects the chord and the arcs subtended by it . P M B Given the line PQ through the center O of the circle AQBP , perpendicular to the chord AB at M. Το prove that AM = BM , arc AQ = arc BQ , and arc AP = arc BP . Proof . Then ...
... chord bisects the chord and the arcs subtended by it . P M B Given the line PQ through the center O of the circle AQBP , perpendicular to the chord AB at M. Το prove that AM = BM , arc AQ = arc BQ , and arc AP = arc BP . Proof . Then ...
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Vanlige uttrykk og setninger
AABC ABCD altitude angles are equal apothem bisector bisects called chord circular cone circumference circumscribed coincide cone of revolution congruent conic surface construct COROLLARY cube diagonal diameter dihedral angles distance draw equidistant equilateral triangle equivalent EXERCISE face angles figure Find the area Find the locus Find the volume frustum given circle given line given point greater hypotenuse inscribed intersection isosceles triangle lateral area lateral edges lateral faces lune measured by arc mid-point number of sides oblique parallel lines parallelogram perimeter perpendicular plane geometry plane MN polyhedral angle polyhedron Proof proportional prove quadrilateral radii radius ratio rectangle rectangular parallelepiped regular polygon regular pyramid right angle right prism right section right triangle segments slant height sphere spherical polygon spherical triangle square straight angle straight line surface symmetric tangent tetrahedron THEOREM triangle ABC trihedral vertex vertices
Populære avsnitt
Side 67 - The line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of the third side.
Side 360 - Similar cylinders are to each other as the cubes of their altitudes, or as the cubes of the diameters of their bases.
Side 190 - If in a right triangle a perpendicular is drawn from the vertex of the right angle to the hypotenuse : I.
Side 152 - If the product of two quantities is equal to the product of two others, either two may be made the extremes of a proportion and the other two the means.
Side 54 - America, but know that we are alive, that two and two make four, and that the sum of any two sides of a triangle is greater than the third side.
Side 31 - In an isosceles triangle the angles opposite the equal sides are equal.
Side 77 - If two triangles have two sides of the one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second. Given A ABC and A'B'C...
Side 51 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 22 - The following are the most important axioms used in geometry: 1. If equals are added to equals the sums are equal. 2. If equals are subtracted from equals the remainders are equal. 3. If equals are multiplied by equals the products are equal. 4. If equals are divided by equals the quotients are equal.
Side 213 - The square constructed upon the sum of two lines is equivalent to the sum of the squares constructed upon these two lines, increased by twice the rectangle of these lines.