Yale Examination PapersGinn, Heath & Company, 1892 - 139 sider |
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Resultat 1-5 av 26
Side 1
... Divide 0.314 by 1.785 . ( 5 ) Multiply 0.785 by 0.0191 . 5. Extract the square root of } to four decimal places . 6. Extract the cube root of 18.65 to two decimal places . 7. If 12 yds . of silk that is yd . wide will make a dress , how ...
... Divide 0.314 by 1.785 . ( 5 ) Multiply 0.785 by 0.0191 . 5. Extract the square root of } to four decimal places . 6. Extract the cube root of 18.65 to two decimal places . 7. If 12 yds . of silk that is yd . wide will make a dress , how ...
Side 2
... Divide 6 by 0.089 , and extract the cube root of the quotient to two decimal places . 4. What is the value , at $ 4500 per acre , of a piece of ground containing 30 rds . 19 ft . 89 in . ? 5. How many liters in a box 1.2m long , 8cm ...
... Divide 6 by 0.089 , and extract the cube root of the quotient to two decimal places . 4. What is the value , at $ 4500 per acre , of a piece of ground containing 30 rds . 19 ft . 89 in . ? 5. How many liters in a box 1.2m long , 8cm ...
Side 3
... Divide 2700hl by 90c1 . 1881 . 33 1. Divide of of by and add the quotient to - 3–75 . 2. Find 9 510 to three decimal places . 3. Find , to three decimal places , the number which has to 0.649 the same ratio which 58 has to 634 . 4. A ...
... Divide 2700hl by 90c1 . 1881 . 33 1. Divide of of by and add the quotient to - 3–75 . 2. Find 9 510 to three decimal places . 3. Find , to three decimal places , the number which has to 0.649 the same ratio which 58 has to 634 . 4. A ...
Side 4
Yale University. 1883 . 1. Divide 82.1 by 41 , 8.21 by 0.41 , and 0.821 by 410 . Carry the result in each case to four decimal places . 2. Find the value to three decimal places of √ ( 0.146 ) 2 + ( 0.063 ) 2 . 3. Divide 38 +8 +12 3 of ...
Yale University. 1883 . 1. Divide 82.1 by 41 , 8.21 by 0.41 , and 0.821 by 410 . Carry the result in each case to four decimal places . 2. Find the value to three decimal places of √ ( 0.146 ) 2 + ( 0.063 ) 2 . 3. Divide 38 +8 +12 3 of ...
Side 5
... Divide 12 x1 . - 192 by 3x by α - b 2. Divide x2 + a b 3. Solve the equation 21 + - 3 x - 6 . 16 m . 11 5x - 5 97-7x + 8 2 4. Find the product of a1 , a3 , aa , and a− * . 5. Solve the equation 15 72-6x x - 2 . 2 x2 6. Find six ...
... Divide 12 x1 . - 192 by 3x by α - b 2. Divide x2 + a b 3. Solve the equation 21 + - 3 x - 6 . 16 m . 11 5x - 5 97-7x + 8 2 4. Find the product of a1 , a3 , aa , and a− * . 5. Solve the equation 15 72-6x x - 2 . 2 x2 6. Find six ...
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Side 59 - Hanc olim veteres vitam coluere Sabini, hanc Remus et frater, sic fortis Etruria crevit scilicet et rerum facta est pulcherrima Roma, septemque una sibi muro circumdedit arces.
Side 12 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Side 15 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 54 - Redit agricolis labor actus in orbem, atque in se sua per vestigia volvitur annus.
Side 47 - Hos ego digrediens lacrimis affabar obortis : Vivite felices, quibus est fortuna peracta Jam sua ; nos alia ex aliis in fata vocamur. Vobis parta quies ; nullum maris aequor arandum, 495 Arva neque Ausoniae semper cedentia retro Quaerenda.
Side 127 - Every section of a circular cone made by a plane parallel to the base is a circle.
Side 126 - If a straight line is perpendicular to each of two straight lines at their point of intersection, it is perpendicular to the plane of those lines.
Side 40 - Homines enim ad deos nulla re propius accedunt quam salutem hominibus dando. Nihil habet nee fortuna tua majus, quam ut possis, nee natura melius, quam 5 ut velis servare quam plurimos.
Side 50 - ... mellaque decussit foliis ignemque removit, et passim rivis currentia vina repressit, ut varias usus meditando extunderet artes paulatim et sulcis frumenti quaereret herbam. [ut silicis venis abstrusum excuderet ignem...
Side 11 - If a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part. Let the straight line AB be divided into any two parts in the point C; the squares of AB, BC are equal to twice the rectangle AB, BC, together with the square of AC.