Mathematics: Compiled from the Best Authors, and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Volum 1W. Hilliard, 1808 |
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Resultat 1-5 av 37
Side 36
... diameter of a Winchester bushel is 18 in- ches , and its depth 8 inches . And one gallon by dry meas- ure contains 2684 cubic inches . - By this measure , salt , lead , ore , oysters , corn , and other dry goods are measured . ALE AND ...
... diameter of a Winchester bushel is 18 in- ches , and its depth 8 inches . And one gallon by dry meas- ure contains 2684 cubic inches . - By this measure , salt , lead , ore , oysters , corn , and other dry goods are measured . ALE AND ...
Side 345
... diameter of a circle is a right line , drawn through the centre , and terminating in the circumference on both sides . 47. An arc of a circle is the circumference . D any part of 48. A chord is a right line , joining the GEOMETRY . 345.
... diameter of a circle is a right line , drawn through the centre , and terminating in the circumference on both sides . 47. An arc of a circle is the circumference . D any part of 48. A chord is a right line , joining the GEOMETRY . 345.
Side 357
... diameter . Bisect CD in the point O , which will be the centre . * A PROBLEM XIII . To describe the circumference of a circle through three given points A , B , C , which are not in a right line . From the middle point B draw right ...
... diameter . Bisect CD in the point O , which will be the centre . * A PROBLEM XIII . To describe the circumference of a circle through three given points A , B , C , which are not in a right line . From the middle point B draw right ...
Side 361
... diameter AB of the given cir- cle ; and divide the radius CB , in the point D , in extreme and mean ratio , by the last Problem . From the point B apply the chords BE , BF , each equal to CD ; then join AE , AF , EF , and AEF will be ...
... diameter AB of the given cir- cle ; and divide the radius CB , in the point D , in extreme and mean ratio , by the last Problem . From the point B apply the chords BE , BF , each equal to CD ; then join AE , AF , EF , and AEF will be ...
Side 367
... being carried round the circum- ference the proper number of times , will complete the figure , Or , the arc AB will be one of the equal parts of the circum- ference . ANOTHER METHOD , NEARLY TRUE . Draw the diameter A GEOMETRY . 367.
... being carried round the circum- ference the proper number of times , will complete the figure , Or , the arc AB will be one of the equal parts of the circum- ference . ANOTHER METHOD , NEARLY TRUE . Draw the diameter A GEOMETRY . 367.
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Mathematics: Compiled from the Best Authors, and Intended to be the ..., Volum 2 Samuel Webber Uten tilgangsbegrensning - 1808 |
Vanlige uttrykk og setninger
affirmative amount of 11 angle annuity annum arithmetical Bisect carats cent centre chord circle circumference coefficient common denominator completing the square compound interest compound quantity consequently cube root debt decimal denoted diameter difference Divide dividend division divisor draw equal equation EXAMPLES exponent figure fourth gallons geometrical progression geometrical series give given number greater greatest common measure half improper fraction infinite series less number logarithm manner Multiply negative NOTE nth root number of combinations number of terms number of things payment perpendicular polygon present worth PROBLEM proportion quadratic equation quotient radius ratio Reduce remainder repetend required to find right line RULE sides simple interest sine square root subtract Suppose surd taken tangent third unknown quantity vulgar fraction Whence whole number yards
Populære avsnitt
Side 175 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Side 140 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 255 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Side 198 - A man was hired 50 days on these conditions. — that, for every day he worked, he should receive $ '75, and, for every day he was idle, he should forfeit $ '25 ; at the expiration of the time, he received $ 27'50 ; how many days did he work...
Side 149 - To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Side 315 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Side 124 - As the sum of the several products, Is to the whole gain or loss ; So is each man's particular product, To his particular share of the gain or loss.
Side 139 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Side 120 - When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Side 132 - When one of the ingredients is limited to a certain quantity. RULE. Take the difference between each price and the mean rate, as before ; then,