Mathematics: Compiled from the Best Authors, and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Volum 1W. Hilliard, 1808 |
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Side 14
... given , there is another very ingenious one of proving addition by casting out the nines . RULE . * 1. Add the figures in the first line , and find how many nines are contained in their sum . 2. Reject the nines and set the remainder in ...
... given , there is another very ingenious one of proving addition by casting out the nines . RULE . * 1. Add the figures in the first line , and find how many nines are contained in their sum . 2. Reject the nines and set the remainder in ...
Side 15
... given to the number 9 , on account of its being more convenient in practice . Now from the demonstration here given , the reason of the rule itself is evident ; for the excess of nines in each of two or METHOD OF PROOF . 1. Draw a line ...
... given to the number 9 , on account of its being more convenient in practice . Now from the demonstration here given , the reason of the rule itself is evident ; for the excess of nines in each of two or METHOD OF PROOF . 1. Draw a line ...
Side 33
... given dividend ; consequently every unit of it , that remains , will contain the same ; therefore this remain- der must be multiplied by 9 , in order to find the units of the given dividend , which it contains . Again , every unit in ...
... given dividend ; consequently every unit of it , that remains , will contain the same ; therefore this remain- der must be multiplied by 9 , in order to find the units of the given dividend , which it contains . Again , every unit in ...
Side 60
... given denominator . RULE . * Multiply the whole number by the given denominator , and place the product over the said denominator , and it will form the fraction required , 12 . EXAMPLES . 1. Reduce 7 to a fraction , whose denominator ...
... given denominator . RULE . * Multiply the whole number by the given denominator , and place the product over the said denominator , and it will form the fraction required , 12 . EXAMPLES . 1. Reduce 7 to a fraction , whose denominator ...
Side 62
... given fractions to others , which shall have the least common denominator . 1. Find the least common multiple of all the denomina- * By placing the numbers multiplied properly under one an- other , it will be seen , that the numerator ...
... given fractions to others , which shall have the least common denominator . 1. Find the least common multiple of all the denomina- * By placing the numbers multiplied properly under one an- other , it will be seen , that the numerator ...
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Mathematics: Compiled from the Best Authors, and Intended to be the ..., Volum 2 Samuel Webber Uten tilgangsbegrensning - 1808 |
Vanlige uttrykk og setninger
affirmative amount of 11 angle annuity annum arithmetical Bisect carats cent centre chord circle circumference coefficient common denominator completing the square compound interest compound quantity consequently cube root debt decimal denoted diameter difference Divide dividend division divisor draw equal equation EXAMPLES exponent figure fourth gallons geometrical progression geometrical series give given number greater greatest common measure half improper fraction infinite series less number logarithm manner Multiply negative NOTE nth root number of combinations number of terms number of things payment perpendicular polygon present worth PROBLEM proportion quadratic equation quotient radius ratio Reduce remainder repetend required to find right line RULE sides simple interest sine square root subtract Suppose surd taken tangent third unknown quantity vulgar fraction Whence whole number yards
Populære avsnitt
Side 175 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Side 140 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 255 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Side 198 - A man was hired 50 days on these conditions. — that, for every day he worked, he should receive $ '75, and, for every day he was idle, he should forfeit $ '25 ; at the expiration of the time, he received $ 27'50 ; how many days did he work...
Side 149 - To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Side 315 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Side 124 - As the sum of the several products, Is to the whole gain or loss ; So is each man's particular product, To his particular share of the gain or loss.
Side 139 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Side 120 - When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Side 132 - When one of the ingredients is limited to a certain quantity. RULE. Take the difference between each price and the mean rate, as before ; then,