 | William Galbraith - 1827 - 412 sider
...Centre. Rule I. — Multiply the tabular value of S by 4 times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Rule II. — 1. Compute the ultimate deflection by Prob. V. ; square that deflection,... | |
 | 1829 - 906 sider
...faced at one end, and loaded at the other. Rule. Multiply the number in the table of multiplicands, by the breadth and square of the depth, both in inches,...divide that product by the length, also, in inches; the quotient will be the weight in Jbs.t Example 1. What weight will it require to break a beam of... | |
 | Charles Hutton - 1831 - 656 sider
...to its centre : how much will it be deflected before it breaks ? Ans. 13-1 inches. PKOB. vi. To fail the ultimate transverse Strength of any rectangular...in inches, and the quotient will be the weight in Iba. This is approximative. Rule. n. 1. Take the ultimate deflection 8 times that of the last problem,... | |
 | Charles Hutton - 1831 - 662 sider
...Centre. . • Ride i. Multiply the tabular value of s by 4 times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Rule u. 1. Compute the ultimate deflection by Prob. v. . square that deflection, and... | |
 | James Hann, Isaac Dodds - 1833 - 234 sider
...Rule. Multiply the value given in the table of data by four times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Example 1. What weight will be necessary to 'break a beam of Canadian oak, the length... | |
 | Andrew Bell - 1842 - 402 sider
...fixed at one end, and loaded at the other. 1 Find the continued product of the tabular value of S, the breadth and square of the depth, both in inches, and divide this product by the length in inches, and the quotient will be the weight in pounds.1 Or, W „ . ld*S... | |
 | James Hann - 1848 - 352 sider
...— Multiply the value given in the table of data by four times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Ex. 1. — What weight will be necessary to break a beam of Canadian oak, the length... | |
 | George Beecroft - 1857 - 350 sider
...one end and 1oaded at the other. RULE. — Mu1tipIy the tabuIar va1ue of S, (see TabIe 2, Page 197), by the breadth and square of the depth, both in inches, and divide that product by the 1ength a1so in inches ; the quotient wi11 be the weight in Ibs.t ExampIe I. — What weight wi11 it... | |
 | Andrew Murray - 1861 - 262 sider
...piece of timber fixed at one end and loaded at the other: — RULE. — Multiply the value given in the table of data by the breadth and square of the depth, both in inches, anil divide the product by the length, also in inches ; the quotient will be the breaking weights in... | |
 | Samuel Griffiths - 1873 - 592 sider
...fixed at mic end and loaded at the other. RULE. — Multiply the tabular value of S (see Table 2), by the breadth and square of the depth, both in inches,...and divide that product by the length also in inches ; the quotient will be the weight in Ibs.2 Example I. — What weight will it require to break a beam... | |
| |
Multiply the number in the table of multiplicands, by the breadth and square of the depth, both in inches, and divide that product by the length, also, in inches; the quotient will be the weight in Jbs.t Example 1. 