| Samuel Webber - 1801
...; what had he at first ? Ans. 2os. 21. To divide the number 90 into 4 such parts, that if the first **be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by** 2t" the sum, difference, product, and quotient, shall be all equal to each other. Ans. The parts are... | |
| Bewick Bridge - 1818 - 227 sider
...inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first **increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2,** may all be equal to the same quantity. ANSW. 18, 22, 10, 40. Qu. 34. A merchant has two kinds often,... | |
| Adrien Marie Legendre - 1819 - 208 sider
...value triple that of the first : what is the value of each horse ? Ans. one 30l. and the other 402. 64. **To divide the number 90 into four such parts that if the first** be increased by Z, the second diminished by 2, the third multiplied by 2, and the fourth divided by... | |
| Bewick Bridge - 1821 - 227 sider
...inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first **increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2,** may all be equal to the same quantity. ANSW. 18,22,10,40. Qu. 34. A merchant has two kinds of tea,... | |
| 1825
...-(- 12 won. lost. remaining. or, 12 x = 12, and x = 1 ; Therefore, 28 x = 28«. money at first. 2. **It is required to divide the number 90 into four such parts, that if the first** be increased by 2 ; the second diminished by 2; the third multiplied by 2; and the fourth divided by... | |
| Silvestre François Lacroix - 1825 - 276 sider
...value triple that of the first : what is the value of each horse Ans. one 301. and the other 401. 64. **To divide the number 90 into four such parts that if the first** be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by... | |
| Warren Colburn - 1825 - 372 sider
...as many as both ol you will have left. How many had each ? 5. It is required to divide the number 72 **into four such parts, that if the first part be increased by** 5, the second part diminished by 5, the third part multiplied by 5, and the fourth part divided by... | |
| Jeremiah Day - 1827 - 332 sider
...each horse ? Ans. 56 and 33 guineas. Prob. 30. Divide the number 90 into 4 such parts, that the first **increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2,** shall all be equal. If x, y, and z, be three of the parts, the fourth will be 90 — x—y — z. And... | |
| Warren Colburn - 1828 - 276 sider
...as many as both of you will have left. How many had each ? 5. It is required to divide the number 72 **into four such parts, that if the first part be increased by** 5, the second part diminished by 5, the third part multiplied by 5, and the fourth part divided by... | |
| John Bonnycastle - 1829 - 312 sider
...much as 3 of the hare's ; how many leaps must the greyhound take to catch the hare ? Ans. 300. J2. **It is required to divide the number 90 into four such...the second diminished by 2, the third multiplied by** i?, and tht fourth divided by 2, the sum, difference, product, and quotient, shall be all equal ? Ans.... | |
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