An elementary course of mathematics, Volum 2 |
Inni boken
Resultat 1-5 av 14
Side 2
... polygon be inscribed in another polygon , the perimeter of the inscribed polygon is less than the perimeter of the other . PROP . III . THEOR . If the chord of [ 2 ] SUPPLEMENT TO PLANE GEOMETRY .
... polygon be inscribed in another polygon , the perimeter of the inscribed polygon is less than the perimeter of the other . PROP . III . THEOR . If the chord of [ 2 ] SUPPLEMENT TO PLANE GEOMETRY .
Side 4
... polygon described about the circle . PROP . IV . THEOR . The perimeters of similar polygons inscribed in circles are ... polygon ABCDEF is to the peri- meter of the polygon GHIKLM as the diameter AD to the dia- meter GK . Join BD , AC ...
... polygon described about the circle . PROP . IV . THEOR . The perimeters of similar polygons inscribed in circles are ... polygon ABCDEF is to the peri- meter of the polygon GHIKLM as the diameter AD to the dia- meter GK . Join BD , AC ...
Side 5
... polygon be inscribed , and an equilateral polygon of the same number of sides be described about the circle , the perimeter of the inscribed polygon will be to the perimeter of the circumscribed , as the perpendicular from the centre on ...
... polygon be inscribed , and an equilateral polygon of the same number of sides be described about the circle , the perimeter of the inscribed polygon will be to the perimeter of the circumscribed , as the perpendicular from the centre on ...
Side 6
... polygon ABCD & c .; therefore the whole polygon is equal to the rectangle contained by half the peri- meter and the perpendicular RT . In the same manner it appears that the area of the circumscribing polygon IKLMN & c . is equal to the ...
... polygon ABCD & c .; therefore the whole polygon is equal to the rectangle contained by half the peri- meter and the perpendicular RT . In the same manner it appears that the area of the circumscribing polygon IKLMN & c . is equal to the ...
Side 7
... polygons of which PQ and AL are the sides , is less than the given line DE . Let the perimeter of the equilateral circumscribed polygon of which PQ is the side be designated by C , and that of the similar inscribed polygon by I , then C ...
... polygons of which PQ and AL are the sides , is less than the given line DE . Let the perimeter of the equilateral circumscribed polygon of which PQ is the side be designated by C , and that of the similar inscribed polygon by I , then C ...
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Vanlige uttrykk og setninger
ABCD allel altitude angle formed angle of inclination auxiliary plane circle described circumference circumscribed coincide cone consequently construction Descriptive Geometry determined diameter dicular dihedral angle contained distance ellipse equal and similar equal bases equilateral polygon faces ASB figure given angle given plane given point given straight line greater hemisphere horizontal plane horizontal projection horizontal trace inscribed isometric line joining line of level line parallel meets the plane parallel planes parallel to xy parallelepiped parallelogram pendicular perimeter perpen perpendicular to xy plane angles plane MN plane passing plane Prop planes BM planes of projection point of intersection prism Prob PROBLEM projecting plane pyramid rectangle right angles right-angled triangle scale of slope series of cylinders sides solid angle space straight line drawn THEOR third face trihedral vertical plane vertical projection vertical trace Wherefore
Populære avsnitt
Side 5 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 18 - FD. Join AC, BD, AD, and let AD meet the plane KL in the point X; and join EX, XF. Because the two parallel planes KL, MN are cut by the plane EBDX, the common sections EX, BD are parallel (Prop.
Side 13 - For the same reason, CD is likewise at right angles to the plane HGK. Therefore AB, CD are each of them at right angles to the plane HGK.
Side 4 - BC above it : and since the straight line AB is in the plane, it can be produced in that plane : let it be produced to D ; and let any plane pass through the straight line AD, and be turned about it until it pass through the point C; and because the points B, C, are in this plane, the straight line* BC is in it: »7Def.1.
Side 9 - Note. (3. 11.) line; let this be BF: therefore the three straight lines AB, BC, BF are all in one plane, viz. that which passes through AB, BC : and because AB stands at right angles to each of the straight lines BD, BE, it is also at right angles (4. 1 1.) to the plane passing through them; and therefore makes right angles (3.
Side 16 - BGH are together equal* to two right angles: and BGH is a right angle; therefore also GBA is a right angle, and GB perpendicular to BA. For the same reason GB is perpendicular to BC. Since therefore the straight line GB stands at right angles to the two straight lines BA, BC, that cut one another in B, GB is perpendicular...
Side 9 - If three straight lines meet all in one point, and a straight line stand at right angles to each of them in that point ; these three straight lines are in one and the same plane. Let the straight line AB stand at right angles to each of the straight lines BC, BD, BE, in B, the point where they meet ; BC, BD, BE are in one and the same plane. If not, let...
Side 1 - A plane is perpendicular to a plane, when the straight lines drawn in one of the planes perpendicular to the common section of the two planes, are perpendicular to the other plane. 5. The inclination of a straight line to a plane...
Side 28 - Cor. 1.) therefore all the angles of the triangles are equal to all the angles of the polygon together with four right angles : (i. ax. 1.) but all the angles at the bases of the triangles are greater than all the angles of the polygon, as has been proved ; wherefore the remaining angles of the triangles, viz. those of the vertex, which contain the solid angle at A, are less than four right angles.
Side 5 - If a straight line stand at right angles to each of two straight lines in the point of their intersection, it will also be at right angles to the plane in which these lines are.