The Squared Circle: Being a Short Treatise, Describing the Manner by which Its True Area and Boundary Were DiscoveredM. Ward & Company, 1884 - 23 sider |
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Side 8
... per cal . No. 35 , from that of the entire circle , per cal . No. 34 , the area of the 12 outside arcs will appear ... each of these chords of the 12 arcs , and connect these points by 12 right lines , passing through and cutting off 12 ...
... per cal . No. 35 , from that of the entire circle , per cal . No. 34 , the area of the 12 outside arcs will appear ... each of these chords of the 12 arcs , and connect these points by 12 right lines , passing through and cutting off 12 ...
Side 9
... shown in cal . No. 20. I will next direct attention to Fig . 9 , where will be found the area of polygon No. 2 , represented by 12 triangles , and also 6 squares , each square being of 4 inches area , all making together as per cal . No ...
... shown in cal . No. 20. I will next direct attention to Fig . 9 , where will be found the area of polygon No. 2 , represented by 12 triangles , and also 6 squares , each square being of 4 inches area , all making together as per cal . No ...
Side 10
... per cal . No. 25 , in excess of the circular area of the hexagon . Now we shall find , by cal . No. 13 , that this ... appears per cals . Nos . 36 , 37 , and 38 , will exactly make up the area of the 3 triangles , as per cal . No. 39 ...
... per cal . No. 25 , in excess of the circular area of the hexagon . Now we shall find , by cal . No. 13 , that this ... appears per cals . Nos . 36 , 37 , and 38 , will exactly make up the area of the 3 triangles , as per cal . No. 39 ...
Side 17
... shown , per cals . Nos . × 26 , × 27 , and x 28 , to be perfectly correct to the extent of 80 decimals . I have also ... per cal . No. x 29 ; and next , by multiplying the boundary by one - fourth of said diameter , per cal . No. 30 , or ...
... shown , per cals . Nos . × 26 , × 27 , and x 28 , to be perfectly correct to the extent of 80 decimals . I have also ... per cal . No. x 29 ; and next , by multiplying the boundary by one - fourth of said diameter , per cal . No. 30 , or ...
Side 18
... appears per cal . No. x 38. Now , from the facts already stated , the area of a circle of 24 inches circumference may be regarded as being composed of ten parts , nine of which ( in the form of a polygon ) represent the area of the ...
... appears per cal . No. x 38. Now , from the facts already stated , the area of a circle of 24 inches circumference may be regarded as being composed of ten parts , nine of which ( in the form of a polygon ) represent the area of the ...
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The Squared Circle: Being A Short Treatise, Describing the Manner by Which ... James Bailey Andrews Ingen forhåndsvisning tilgjengelig - 2009 |
Vanlige uttrykk og setninger
12 arcs 16 inches 18 circular rings 18 triangles 24 inches 24 triangles absolute amount angular boundary angular measurement appears per cal area and boundary area of 48 area of cal bisect boundaries and areas calculations centre circular and spherical circular ring measurement circular ring mode circumscribing circle circumscribing polygon deducting the area described duplication entire circle equal in area equilateral triangle Euclid Euclid's exactly equal excess extent of 80 form the chords give the area give the true given at cal hypotenuse hypothesis inches diameter inscribed circle investigation linear extent linear measure mode of enquiry obtain one-fourth the area one-fourth the diameter one-half one-sixth perfect circle polygon sides radius regarded relative proportion represented by cal right angle right lines drawn right-angled triangle second polygon six arcs spherical geometry square of 16 square root triangles will equal true area true boundary true circular boundary true circumference true proportional
Populære avsnitt
Side 22 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 6 - ... right-angled triangle (ABC) the square which is described upon the side (AC) subtending the right angle is equal to the sum of the squares described upon the sides (AB and CB) which contain the right angle.