| 1867 - 964 sider
...to show. The reader will remember that in Problem XXIV (page 308) it was shown that triangles on the **same base and between the same parallels are equal to one another,** and that triangles on equal bases and between the same parallels are also equal to one another. Now... | |
| John Playfair - 1806 - 320 sider
...also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. QED PROP. XXXVII. THEOR. **TRIANGLES upon the same base, and between the same parallels, are equal to one another.** Let the triangles ABC, DEC be upon the same base BC, and between the same parallels AD, BC; the triangle... | |
| Robert Simson - 1806 - 518 sider
...parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. QED An ; . PROP. XXXVII. THEOR. **TRIANGLES upon the same base, and between the same parallels, are equal to one another.** Let the triangles ABC, DBC be upon the same base RC"and between the same parallels AD, BC : the triangle... | |
| John Mason Good - 1813 - 722 sider
...diameter bisects them, that is, divides them in two equal parts. Prop. XXXV. Theor. Parallelograms **upon the same base and between the same parallels, are equal to one another.** Prop. XXXVI. Theor. Parallelograms upon equal basis, and between the same parallels, are equal to one... | |
| Euclides - 1816 - 528 sider
...also the parallelogram ABCD is equal to EFGH. Wherefore parallelograms, &c. QED PROP. XXXVII. THEOR. **TRIANGLES upon the same base, and between the same parallels, are equal to one another.** Let the triangles ABC, DBC, be upon the same base BC, and between thesame p \ r\ parallels AD, BC :... | |
| John Playfair - 1819 - 317 sider
...the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. Q, ED PROP. XXXVII. THEOR. **Triangles upon the same base, and between the same parallels, are equal to one another.** AD Let the triangles ABC, DBC be upon the same base BC, and between the same parallels AD, BC : The... | |
| Peter Nicholson - 1825 - 372 sider
...divides the parallelogram ACDB into two eqoal parts, QED Proposition XXXV. Theorem. Parallelograms **upon the same base, and between the same parallels, are equal to one another.** Let the parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF BC ;... | |
| Euclid - 1826 - 236 sider
...shall the two trapeziums be equal to one another. PROPOSITION XXXVII. THEOREM. Triangles constituted **upon the same base, and between the same parallels, are equal to one another.** Let the triangles ABC, DBC, be constituted upon the same base вс, and between the same parallels... | |
| Euclides - 1826 - 226 sider
...shall the two trapeziums be equal to one another. PROPOSITION XXXVII. THEOREM. Triangles constituted **upon the same base, and between the same parallels, are equal to one another.** » 3i. i. parallel to сл, " and through c draw CF, parallel to в D. Therefore each of them EBCA,... | |
| Robert Simson - 1827 - 513 sider
...diameter BC divides the parallelogram ACDB into two equal parts.' ei. ED PROP. XXXV. THEOR. Parallelograms **upon the same base, and between the same parallels, are equal to one another.** Let the parnllelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, BC :... | |
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