Elements of Euclid Adapted to Modern Methods in GeometryWilliam Collins, Sons,, 1874 - 216 sider |
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Side 13
... two radii drawn through its extremities . 37. When the two radii of a sector are at right angles to one another , the sector is called a quadrant . 38. The altitude of any figure is the straight line DEFINITIONS . 13.
... two radii drawn through its extremities . 37. When the two radii of a sector are at right angles to one another , the sector is called a quadrant . 38. The altitude of any figure is the straight line DEFINITIONS . 13.
Side 14
Euclid, James Bryce, David Munn (F.R.S.E.). 38. The altitude of any figure is the straight line drawn from its vertex perpendicular to its base . So also are two angles 39. Two arcs , whose sum is the arc of a semicircle , are called ...
Euclid, James Bryce, David Munn (F.R.S.E.). 38. The altitude of any figure is the straight line drawn from its vertex perpendicular to its base . So also are two angles 39. Two arcs , whose sum is the arc of a semicircle , are called ...
Side 48
... altitude , are equal in area . M- P B D G F H N Q Let ABC and DEF be on equal bases and of the same altitude , they are equal in area . E ( I. 22. ) ( I. 27. ) From B and E , the extremities of the equal bases , draw BG and EH parallel ...
... altitude , are equal in area . M- P B D G F H N Q Let ABC and DEF be on equal bases and of the same altitude , they are equal in area . E ( I. 22. ) ( I. 27. ) From B and E , the extremities of the equal bases , draw BG and EH parallel ...
Side 50
... altitude must stand upon equal bases . For if the bases are not equal , cut off from EF a part EK equal to BC ; join DK ; then by this Prop . , and by hypothesis , DEK and DEF are both equal to ABC , which is impossible ( Ax . 9. ) PROP ...
... altitude must stand upon equal bases . For if the bases are not equal , cut off from EF a part EK equal to BC ; join DK ; then by this Prop . , and by hypothesis , DEK and DEF are both equal to ABC , which is impossible ( Ax . 9. ) PROP ...
Side 64
... altitude , and since the altitude is equal to the side of the rectangle , it follows that the area of any parallelogram will be found by multiplying the base by the altitude ; that is , b being the base and a the altitude of any ...
... altitude , and since the altitude is equal to the side of the rectangle , it follows that the area of any parallelogram will be found by multiplying the base by the altitude ; that is , b being the base and a the altitude of any ...
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Elements of Euclid, Adapted to Modern Methods in Geometry. By J. Bryce ... Uten tilgangsbegrensning - 1874 |
Elements of Euclid Adapted to Modern Methods in Geometry Euclid,James Bryce,David Munn (F.R.S.E.) Ingen forhåndsvisning tilgjengelig - 1874 |
Vanlige uttrykk og setninger
AC and CB altitude angle AOB BA and AC bisecting the angle centre chord circles touch circumference cloth coincide Const conv Cor.-Hence diagonal diameter divided draw equal angles equal to BC equal to twice equiangular equilateral triangle Euclid exterior angle Fcap GEOGRAPHY geometrical given circle given line given point given straight line greater half the perimeter Hence hypotenuse inscribed intersecting isosceles triangle less Let ABC LL.D meet middle point multiple opposite sides parallel to BC parallelogram perpendicular polygon produced Proposition Q. E. D. Cor Q. E. D. PROP radius ratio rectangle contained rectilineal figure reflex angle remaining angles required to prove right angles right-angled triangle schol segments shew shewn side BC square on AC tangent THEOREM triangle ABC twice the rectangle twice the square whole line
Populære avsnitt
Side 68 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Side 77 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Side 50 - If a parallelogram and a triangle be upon the same base, and between the same parallels; the parallelogram is double of the triangle.
Side 87 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section.
Side 30 - Any two sides of a triangle are together greater than the third side.
Side 204 - Tin; rectangle, contained by the diagonals of a quadrilateral inscribed in a circle, is equal to the sum of the rectangles contained by its opposite sides. Let ABCD be any quadrilateral inscribed in a circle...
Side 89 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square on the other part.
Side 98 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.