PROP. X. THEOR. Solid parallelepipeds, which have their bases and altitudes reciprocally proportional, are equal ; and parallelepipeds which are equal, have their bases and altitudes reciprocally proportional. Let AG and KQ be two solid parallelepipeds, of which the bases are AC and KM, and the altitudes AE and KO, and let AC be to KM as KO to AE; the solids AG and KQ are equal. As the base AC to the base KM, so let the straight line KO be to the straight line S. Then, since AC is to KM as Ko to S, and also by hypothesis, AC to KM as KO to AE, KO has the same ratio to S that it has to AE (11. 5.); wherefore AE is equal to S (9. 5.). But the solid AG is to the solid KQ, in the ratio compounded of the ratios of AE to KO, and of AC to KM (9. 3. Sup.), that is, in the ratio compounded of the ratios of AE to ko, and of KO to S. And the ratio of AE to S is also compounded of the same ratios (def. 10. 5.); therefore, the solid AG has to the solid KQ the same ratio that AE has to S. But AE was proved to be equal to S, therefore AG is equal to KQ. Again, if the solids AG and KQ be equal, the base AC is to the base KM as the altitude KO to the altitude AE. Take S, so that AC may be to KM as KO to S, and it will be shewn, as was done above, that the solid AG is to the solid KQ as AE to S; now, the solid AG is, by hypothesis, equal to the solid KQ; therefore, AE is equal to S; but. by construction, AC is to KM, as KO is to S; therefore, AC is to KM as Ko to AE. Therefore, Q. E. D. Cor. In the same manner, may it may be demonstrated, that equal prisms have their bases and altitudes reciprocally proportional, and conversely. PROP. XI. THEOR. Similar solid parallelepipeds are to one another in the triplicate ratio of their homologous sides. Let AG, KQ be two similar parallelepipeds, of which AB and KL are two homologous sides; the ratio of the solid AG to the solid KQ. its triplicate of the ratio of AB to KL. Because the solids are similar, the parallelograms AF, KB are similar (def. 2. 3. Sup.), as also the parallelograms AH, KR; therefore, the ratios of AB to KL, of AE to KO, and of AD to KN are all equal (def. 1. 6.). But the ratio of the solid AG to the solid KQ is compounded of the ratios of AC to KM, and of AE to KO. Now, the ratio of AC to KM, because they ere equiangular parallelograms, is compounded (23. 6.) of the ratios of AB to KL, and of AD to KN. Wherefore, the ratio of AG to KQ is compounded of the three rațios of AB to KL, AD to KN, and AE to KO; and these three ratios have already been proved to be equal; therefore, the ratio that is compounded of them, viz. the ratio of the solid AG to the solid KQ, is triplicate of any of them (def. 12. 5.); it is therefore triplicate of the ratio of Að to KL, Therefore, similar solid parallelepipeds, &c. Q. E. D. Cor. 1. If as AB to KL, so KL to m, and as KL to m, so is m to n, then AB is to n as the solid AG to the solid KQ. For the ratio of AB ton is triplicate of the ratio of AB to KL (def. 12.5.), and is therefore equal to that of the solid AG to the solid KQ. COR. 2. As cubes are similar solids, therefore the cube on AB is to the cube on KL in the triplicate ratio of AB to KL, that is in the same ratio with the solid AG, to the solid KQ. Similar solid parallelepipeds are therefore to one another as the cubes on their homologous sides. Cor. 3. In the same manner it is proved, that similar prisms are to one another in the triplicate ratio, or in the ratio of the cubes of their homologous sides. PROP. XII. THEOR, If two triangular pyramids, which have equal hases and altitudes, be cut by planes that are parallel to the bases, and at equal distances from them, the sections are equal to one another. Let ABCD and EFGH be two pyramids, having equal bases BDC and H, and equal altitudes, viz. the perpendiculars AQ, and ES, S G Because the plane ABD cuts the parallel planes BDC, KLM, the common sections BD and KM are parallel (14. 2. Sup.). For the same reason, DC and ML are parallel. Since therefore KM and ML are parallel to BD and DC, each to each, though not in the same plane with them, the angle KML is equal to the angle BDC (9. 2. Sup.). In like manner the other angles of these triangles are proved to be equal ; therefore, the triangles are equiangular, and consequently similar; and the same is true of the triangles NOP, FGH. Now, since the straight lines ARQ, AKB meet the parallel planes BDC and KML, they are cut by them proportionally (16. 2. Sup.), or QR : RA :: BK: KA; and AQ : AR : : AB : AK (18. 5.), for the same reason, ES : ET :: EF : EN ; therefore, AB : ÀK :: EF : EN, because AQ is equal to ES, and AR to ET. Again, because the triangles ABC, AKL are similar, AB : AK :-; BC: KL; and for the same reason BC : KL :: FG : NO. And, when four straight lines are prou portionals, the similar figures described on them are also proportionals (22. 6.); therefore the triangle BCD is to the triangle KLM as the triangle FGH to the triangle NOP; but the triangles BDC, FGH are equal; therefore, the triangle KLM is also equal to the triangle NOP (1. 5.). Therefore, &c. Q. E. D. Cor. 1. Because it has been shewn that the triangle KLM is similar to the base BCD; therefore, any section of a triangular pyramid parallel to the base, is a triangle similar to the base. And in the same manner it is shewn, that the sections parallel to the base of a polygonal pyramid are similar to the base. Cor. 2. Hence also, in polygonal pyramids of equal bases and alti Dd tudes, the sections parallel to the bases, and at equal distances from them, are equal to one another. PROP. XIII. THEOR. N R A series of prisnis of the same altitude may be circumscribed about any pyramid, such that the sum of the prisms shall exceed the pyramid by a solid less than any given solid. Let ABCD be a pyramid and Z* a given solid ; a series of prisms having all the same altitude, may be circumscribed about the pyramid ABCD, so that their sum shall exceed ABCD, by a solid less than 2. Let Z be equal to a prism standing on the same base with the pyramid, viz. the triangle BCD, and having for its altitude the perpendi W V cular drawn from a certain point E in the line AC upon the plane BCD. It is evident, that CE multiplied by a certain numberm will be greater than T AC ; divide CA into as many equal H parts as there are units in m, and let these be CF, FG, GH, HA, each of I M which will be less than CE. Through each of the points F, G, H let planes be made to pass parallel to the plane K. IG BCD, making with the sides of the pyramid the sections FPQ, GRS, P HTU, which will be all similar to one E another, and to the base BCD (1.cor. 12. 3. Sup.). From the point B B В draw in the plane of the triangle ABC, h the straight line BK parallel to CF meeting FP produced in K. In like manner, from D draw DL parallel to Č CF, meeting FQ in L : Join KL, and it is plain, that the solid KBCDLF is a prism (def. 4. 3. Sup.). By the same construction, let the prisms PM, RO, TV be described. Also, let the straight line IP, which is in the plane of the triangle ABC be produced till it meet BC in b; and let the line MQ, be produced till it meet DC in g: Join hg ; then hCgQFP is a prism, and is equal to the prism PM (1. Cor. 8. 3. Sup.). In the same manner is described the prism MS equal to the prism RO, and the prism qu equal to the prism TV. The sum, therefore, of all the inscribed prisms hQ, ms, and qU is equal to the sum of the prisms PM, RO and TV, that is, to the sum of all the circumscribed prisms except the prism BL; wherefore, BL is the excess of the prisms circumscribed about the pyramid ABCD above the prisms inscribed with m * The solid Z is not represented in the figure of this, or the following Proposition. in it. But the prism BL is less than the prism which has the triangle BCD for its base, and for its altitude the perpendicular from E upon the plane BCD; and theprism which has BCD for its base, and the perpendicular from E for its altitude, is by hypothesis equal to the given solid Z; therefore, the excess of the circumscribed, above the inscribed prisms, is less than the given solid Z. But the excess of the circumscribed prisms above the inscribed is greater than their excess above the pyramid ABCD, because ABCD is greater than the sum of the inscribed prisms. Much more, therefore, is the excess of the circumscribed prisms above the pyramid, less than the solid Z. A series of prisms of the same altitude has therefore been circumscribed about the pyramid ABCD exceeding it by a solid less than the given solid Z. Q. E. D. PROP. XIV. THEOR. Pyramids that have equal bases and altitudes are equal to one another. Let ABCD, EFGH be two pyramids that have equal bases BCD, FGH, and also equal altitudes, viz. the perpendiculars drawn from the vertices A and E upon the planes, BCD, FGH: The pyramid ABCD is equal to the pyramid EFGH. If they are not equal, let the pyramid EFGH exceed the pyramid ABCD by the solid Z. Then, a series of prisms of the same altitude G may be described about the pyramid ABCD that shall exceed it, by a solid less than Z (13. 3. Sup.) ; let these be the prisms that have for their bases the triangles BCD, NQL, ORI, PSM. Divide EH into the same number of equal parts into which AD is divided, viz HT, TU, UV, VE, and through the points T, U and V, let the sect ons |