A Treatise on Spherics: Comprising the Elements of Spherical Geometry, and of Plane and Spherical Trigonometry, Together with a Series of Trigonometrical TablesJ. Mawman, 1816 - 294 sider |
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Side ix
... solved in two very different ways : it is important , that he compare the two methods with one another , in order fully to apprehend the nature of the advantage , which the Algebraical method has , over the Geometrical : and , whilst he ...
... solved in two very different ways : it is important , that he compare the two methods with one another , in order fully to apprehend the nature of the advantage , which the Algebraical method has , over the Geometrical : and , whilst he ...
Side 39
... solved by what has been premised . But , the passage from theory to practice cannot be effected , unless the possibility of certain graphical operations on the surface of a sphere , in addition to those of plane Geometry , be first ...
... solved by what has been premised . But , the passage from theory to practice cannot be effected , unless the possibility of certain graphical operations on the surface of a sphere , in addition to those of plane Geometry , be first ...
Side 59
... . ) Problem . From a given point , on the surface of a given sphere , to draw an arch of a great circle , equal to a given arch of a great circle . The problem is solved , by means of Art . Art . 91. ] 59 SPHERICAL GEOMETRY .
... . ) Problem . From a given point , on the surface of a given sphere , to draw an arch of a great circle , equal to a given arch of a great circle . The problem is solved , by means of Art . Art . 91. ] 59 SPHERICAL GEOMETRY .
Side 60
... solved , by means of Art . 88 , and some of the preceding articles , exactly in the same manner , as the second proposition of the first Book of Euclid's Elements . PROP . VI . ( 92. ) Problem . From the greater of two given arches of ...
... solved , by means of Art . 88 , and some of the preceding articles , exactly in the same manner , as the second proposition of the first Book of Euclid's Elements . PROP . VI . ( 92. ) Problem . From the greater of two given arches of ...
Side 64
... solved by the same construction as is the ninth proposition of the first Book of Euclid's Elements and if the arches which contain the given angle , be arches of great circles , the demonstration rests solely on Art . 86 : but if the ...
... solved by the same construction as is the ninth proposition of the first Book of Euclid's Elements and if the arches which contain the given angle , be arches of great circles , the demonstration rests solely on Art . 86 : but if the ...
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Vanlige uttrykk og setninger
angle opposite base bisect circle EFH circumference co-tangent common section cosine describe a circle describe Art diameter drawn equal and parallel equal arches equal circles equal spheres equal to FE equations Euclid's Elements Find Art fore four right angles given angle given arch given circle given great circle given point given sphere given triangle greater hypotenuse Introd join Art less measure meet oblique angles opposite angle parallel circles perpendicular plane triangle polar distance polar triangle pole Problem PROP proposition quadrantal triangle radius rical triangle right angles right-angled spherical triangle SCHOLIUM semi-circumference shewn side BC sin S sin sine sphe sphere's center sphere's surface spherical angle spherical distance Spherical Geometry spherical polygon spherical tri Spherical Trigonometry straight line tangent Theorem three angles three sides touch the circle triangle ABC trigonometrical functions wherefore
Populære avsnitt
Side 53 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 46 - BC shall be equal to the base EF ; and the triangle ABC to the triangle DEF ; and the other angles, to which the equal sides are opposite, shall be equal, each to each, viz.
Side iii - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 43 - Theorem. If two spherical triangles on the same sphere, or on equal spheres, are equilateral with respect to each other, they are also equiangular with respect to each other.
Side 53 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 53 - BC common to the two triangles, which is adjacent to their equal angles ; therefore their other sides shall be equal, each to each, and the third angle of the one to the third angle of the other, (26.
Side iii - A diameter of a circle is a straight line drawn through the center and terminated both ways by the circumference, as AC in Fig.
Side 132 - If two triangles have two sides and the included angle in the one equal to two sides and the included angle in the other, each to each, the two triangles will be equal.
Side 38 - THEOREM. The sum of the sides of a spherical polygon is less than the circumference of a great circle.
Side 50 - If two angles of a triangle be equal to one another, the sides also which subtend the equal angles shall be equal to one another.