The Elements of Plane and Solid GeometryLongmans, Green, and, Company, 1871 - 285 sider |
Inni boken
Resultat 1-5 av 65
Side 4
... perpendicular or at right angles to the straight line in which the non - coin- cident arms lie . A C B Thus if AOB be a straight line and OC a line such that AOC is equal to BOC , then each of the angles AOC and BOC is called a right ...
... perpendicular or at right angles to the straight line in which the non - coin- cident arms lie . A C B Thus if AOB be a straight line and OC a line such that AOC is equal to BOC , then each of the angles AOC and BOC is called a right ...
Side 27
... perpendicular to the base , for EFC and DFC are right angles , being equal adjacent angles . Fig . 31 . E Corollary 2. - If any number of straight lines , as CD , CE , and CF , be drawn from a point C , in the straight line AB , and on ...
... perpendicular to the base , for EFC and DFC are right angles , being equal adjacent angles . Fig . 31 . E Corollary 2. - If any number of straight lines , as CD , CE , and CF , be drawn from a point C , in the straight line AB , and on ...
Side 31
... perpendicular shall be equal to one another . 2. The perpendicular shall be the shortest line that can be drawn from the given point to the given line , and of any pair of lines unequally inclined to the perpendicular the line nearer to ...
... perpendicular shall be equal to one another . 2. The perpendicular shall be the shortest line that can be drawn from the given point to the given line , and of any pair of lines unequally inclined to the perpendicular the line nearer to ...
Side 32
... perpendicular to AB . Also no other line except CE can be drawn from C at right angles to AB . For , if it were so drawn , we should have two angles of a triangle together equal to two right angles , which is impos- sible , by Prop . 14 ...
... perpendicular to AB . Also no other line except CE can be drawn from C at right angles to AB . For , if it were so drawn , we should have two angles of a triangle together equal to two right angles , which is impos- sible , by Prop . 14 ...
Side 33
... perpendicular to each other . 2. Two straight lines , CA and CB , intersect in a point C , and CO is a line through C bisecting the angle ACB . Prove that if CD be any other line whatever drawn through C , the angle DCO will be equal to ...
... perpendicular to each other . 2. Two straight lines , CA and CB , intersect in a point C , and CO is a line through C bisecting the angle ACB . Prove that if CD be any other line whatever drawn through C , the angle DCO will be equal to ...
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Vanlige uttrykk og setninger
ABC and DEF ABCD adjacent angles angle ABC angle ACB angle BAC BC is equal centre circumference coincide common measure construction Corollary diameter dicular dihedral angle distance divided equal angles equal to AC equidistant exterior angle figure four right angles given angle given circle given plane given point given ratio given straight line greater homologous inscribed intersecting straight lines length less Let ABC line of intersection locus magnitudes meet the circle middle point multiple number of sides opposite sides parallelogram pentagon perpen perpendicular plane AC point F produced Prop PROPOSITION PROPOSITION 13 Prove radii radius rectangle regular polygon respectively equal rhombus right angles segments side BC similar triangles Similarly situated square straight line AB straight line BC subtended tangent triangle ABC triangle DEF
Populære avsnitt
Side 15 - If two triangles have two sides of the one equal to two sides of the...
Side 101 - Through a given point to draw a straight line parallel to a given straight line. Let A be the given point, and BC the given straight line, it is required to draw a straight line through the point A, parallel to the line BC.
Side 126 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Side 222 - The areas of two circles are to each other as the squares of their radii. For, if S and S' denote the areas, and R and R
Side 188 - If the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base ; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Side 204 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side 14 - Upon the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity.
Side 12 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle.
Side 161 - Ir there be any number of magnitudes, and as many others, which, taken two and two in order, have the same ratio ; the first shall have to the last of the first magnitudes the same ratio which the first of the others has to the last. NB This is usually cited by the words