The first book of Euclid's Elements, simplified, explained and illustrated, by W. Trollope1847 |
Inni boken
Resultat 1-5 av 9
Side 38
... vertical , or opposite , angles shall be equal . E B PART . ENUN . - Let the two st . lines AB , CD cut one another in the pt . c . E ; then the AEC shall be = DEB , and the A CEB shall be = AED . DEMONST . - 1 . Because the st . line ...
... vertical , or opposite , angles shall be equal . E B PART . ENUN . - Let the two st . lines AB , CD cut one another in the pt . c . E ; then the AEC shall be = DEB , and the A CEB shall be = AED . DEMONST . - 1 . Because the st . line ...
Side 40
... vertical C 25 CEA , DEB = to one another ; then CE shall be in the same st . line with DE . DEMONST . - 1 . Because the △ CEA = = DEB ( Hyp . ) , add to each the A S E B CEB ; . ' . < CEA + CEB = < CEB and DEb ( Ax . 2 ) . 2. But the ...
... vertical C 25 CEA , DEB = to one another ; then CE shall be in the same st . line with DE . DEMONST . - 1 . Because the △ CEA = = DEB ( Hyp . ) , add to each the A S E B CEB ; . ' . < CEA + CEB = < CEB and DEb ( Ax . 2 ) . 2. But the ...
Side 41
... vertical / DGB ( Prop . XV . ) : i . e . the two st . lines CG , DG , drawn from C , D , and meeting in G , make - / s with AB.-Q. E. F. PROP . XVI . THEOR . GEN . ENUN . - If one side of a triangle be produced , the exterior angle is ...
... vertical / DGB ( Prop . XV . ) : i . e . the two st . lines CG , DG , drawn from C , D , and meeting in G , make - / s with AB.-Q. E. F. PROP . XVI . THEOR . GEN . ENUN . - If one side of a triangle be produced , the exterior angle is ...
Side 42
... vertically op- posite ACD ( Prop . XV . ) , is > than the ABC . Wherefore , if one side of a △ be produced , & c . - Q ... vertical / ACD is > ABC.-Q. E. D. It is observable that the exterior / ACD will be either > , = , or < than the ...
... vertically op- posite ACD ( Prop . XV . ) , is > than the ABC . Wherefore , if one side of a △ be produced , & c . - Q ... vertical / ACD is > ABC.-Q. E. D. It is observable that the exterior / ACD will be either > , = , or < than the ...
Side 65
... . DEMONST . - 1 . Because the AGH = vertical 4 A C E B G F D EGB ( Prop . XV . ) = GHD ( Hyp . ) , and they are alternates ; .. AB is | to CD . ( Prop . XXVII . ) 2. Again , because the S AGH + BGH = PROP . XXVIII . 65.
... . DEMONST . - 1 . Because the AGH = vertical 4 A C E B G F D EGB ( Prop . XV . ) = GHD ( Hyp . ) , and they are alternates ; .. AB is | to CD . ( Prop . XXVII . ) 2. Again , because the S AGH + BGH = PROP . XXVIII . 65.
Vanlige uttrykk og setninger
ABCD adjacent angle contained base BC bisect CD Prop coincide Const CONST.-In CONST.-Join CONST.-Let DEMONST.-Because DEMONST.-For demonstration diam diameter draw EBCF ENUN ENUN.-If ENUN.-Let ABC ENUN.-To ENUN.-To describe equal sides equilateral Euclid EUCLID'S ELEMENTS exterior four rt given point given straight line interior and opposite interior opposite isosceles join Let ABC line be drawn line drawn meet opposite angles opposite sides parallel parallelogram perpendicular Post PROB produced Proposition proved rectilineal figure rhombus right angles side BC square take any pt THEOR THEOR.-If Theorem trapezium trapezium ABCD vertical Wherefore XXIX XXXI XXXII XXXIV XXXVIII
Populære avsnitt
Side 58 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 24 - Upon the same base, and on the same side of it, there cannot be two triangles, that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity, equal to one another.
Side 34 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 6 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 109 - If the square described upon one of the sides of a triangle, be equal to the squares described upon the other two sides of it; the angle contained by these two sides is a right angle.
Side 9 - Parallel straight lines are such as are in the same plane, and which being produced ever so far both ways, do not meet.
Side 99 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 49 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle. Let...
Side 104 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 6 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.