| Popular educator - 1767
...any point in tho straight line HK, produced both ways indefinitely. Triangles also which stand npon **equal bases and between the same parallels are equal to one another.** Thus, the triangles LNG, M o F, which „ ._ stand on equal bases, NG, F o, and K between the same... | |
| Robert Gibson - 1806 - 452 sider
...equal ; for it has been proved that ABCD being a parallelogram, AB will be=CD and AD = BC, THEOREM **XIII, All parallelograms on the same or equal bases...same parallels, are equal to one ' another, that is,** if BD^GH, and the lines BH and AF parallel, then the parallel0gram ABDC ^BDFE=EFHG. .fig. 31. For AC=BD=EF... | |
| Euclid, Robert Simson - 1806 - 518 sider
...is'equal to the triangle DBC. Wherefore, triangles, fee, QE D, PROP. XXXVIII. THEOR. TRIANGLES upon **equal bases, and between the same parallels, are equal to one another.** Let the triangles ABC, DEF be upon equal bases BC, EF, and between the same parallels BF, AD : the... | |
| John Playfair - 1806 - 311 sider
...EBCF. Therefore, parallelograms upon the same base, &c. QED PROP. XXXVI. THEOR. PARALLELOGRAMS upon **equal bases, and between the same parallels, are equal to one another.** Let ABCD, EFGH be parallelograms upon equal bases BC, FG, and between the same parallels AH, BG; the... | |
| Robert Gibson - 1811 - 508 sider
...|»rallelogram E FG H= B DEF. Wherefore ABDC=> BDEF=EFHG. 3. ED Cor. Hence it is plain that triangles **on the same or equal bases, and between the same parallels, are equal,** seoing (by cor. 2. theo. 1Q.) theyavf the halves of their respective parallelogram • THEO. XIV. PL.... | |
| John Mason Good, Olinthus Gilbert Gregory - 1813
...base, and between the same parallels, are equal to one another. Prop. XXXVIII. Theor. Triangles upon **equal bases, and between the same parallels, are equal to one another.** Prop. XXXIX. Theor. Equal triangles upon the same base, and upon the same side of it, are between the... | |
| Robert Gibson - 1814 - 508 sider
...the parallelogram EFGH=BDEF. Wherefore ABDC=BDEF=EFHG. QED ч Cor. Hence it is plain that triangles **on the same or equal bases, and between the same parallels, are equal,** seeing (by cor. 2. theo. 12.) they are the halves of their respective parallelogram. THEO. XIV. PL.... | |
| Euclides - 1816 - 528 sider
...Therefore parallelograms upon the same base, &c. QED 1 PROP. XXXVI. THEOR. Boot I. PARALLELOGRAMS upon **equal bases, and between the same parallels, are equal to one another.** •f> K LetABCD,EFGH,be parallelograms upon equal bases BC,FG, and between the same parallels AH, BG;... | |
| Robert Gibson - 1818 - 478 sider
...prove the parallelogram EFGH=BDEF. Wherefore ABCD=BDEF=EFHG. QED Cor. Hence it is plain that triangles **on the same or equal bases and between the same parallels, are equal,** seeing (by cor. 2. theo. 12.) they are the halves of their respective parallelograms. THEOREM XIV.... | |
| John Playfair - 1819 - 317 sider
...Therefore, parallelograms upon the same base, &c. Q. E%13. PROP. XXXVI. THEOR. Parallelograms upon **equal bases, and between the same parallels, are equal to one another.** Let ABCD, EFGH be parallelograms upon equal bases BC, FG, A DE and between the same parallels AH, BG... | |
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