VI. To find the content of a triangular piece of ground, Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor. A Treatise of Practical Surveying, ... - Side 182av Robert Gibson - 1808 - 440 siderUten tilgangsbegrensning - Om denne boken
| Robert Gibson - 1795 - 319 sider
...thereof • to that of the Bafe, by a Right Line, and thence compleat the Parallelogram. PROB. PR 0 S. **VI. To find the Content of a «Triangular Piece of Ground. Multiply the** Bafe by Half the Perpendicular, or the Perpendicular by Half the Bafe ; or take Half the Product of... | |
| Abel Flint - 1804 - 168 sider
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then **multiply the Base by half the Perpendicular, or the Perpendicular by half the Base** ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the... | |
| Abel Flint - 1808 - 168 sider
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then **multiply the Base by half the Perpendicular, or the Perpendicular by half the Base** ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the... | |
| Robert Gibson - 1811 - 508 sider
...the extremity thereof to that of the base by a right line, and thence completing the parallelogram. **PROB. VI To find the content of a triangular piece...product of the base into the perpendicular. The reason** of this is plain, from cor. 2. theo. 12. eeom. EXAMPLE. PL. 1. Jig. 16. Let ^U^ be a triangular piece... | |
| Robert Gibson - 1814 - 508 sider
...line, and thence completing the parallelogram. PROB. VI. To find the content of a triangular fiiece **of ground. Multiply the base by half the perpendicular,...product of the base into the perpendicular. The reason** of this is plain, from cor. 2. theo. 12. geom. EXAMPLE. PL. i.Jig. 16. Let ABC be a triangular piece... | |
| Robert Gibson - 1818 - 478 sider
...the extremity thereof to that of the base, by a right line ; and thence complete the parallelogram. **PROB. VI. To find the content of a triangular piece...perpendicular. The reason hereof is plain, from cor. 2. theo,** \3.. sect. i. EXAMPLE. D Let ABC be a triangular piece of ground, whose longest side or base BC, is... | |
| Robert Gibson - 1821 - 544 sider
...1 : SZ-A : ; DAXAB ; 8. ^ JxVAXJIi=tke area of the parallelogram. Q. /.s I» , . 9 PROB. VI. Tafnd **the content of a triangular piece of ground. Multiply...product of the base into the perpendicular. The reason** of this is plain, from cor. 2. theo. 12. geom. EXAMPLE. PL. 1. 2ig. 16. Let ABC be a triangular piece... | |
| Anthony Nesbit - 1824 - 434 sider
...are given. RULE. Multiply the base by the perpendicular, and half the product will be the area. Or, **multiply the base by half the perpendicular ; or the perpendicular by half the base,** and the product will be the area. Aote 1. If double the area of a triangle be divided by one of its... | |
| Abel Flint - 1825 - 241 sider
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then **multiply the Base by half the Perpendicular, or the Perpendicular by half the Base** ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the... | |
| James Hale - 1829 - 115 sider
...? Ans. 63x28=1764-r-160=11 Acres 4 Rods. PROBLEM III. To find the Area of a Right Angled Triangle. **Multiply the Base by half the Perpendicular, or the Perpendicular by half the Base,** the Product is the Area; or, multiply the Base and Pe/pendicular together, and half the Product is... | |
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