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Bøker Bok 110 av 15VI. To find the content of a triangular piece of ground, Multiply the base by half...
" VI. To find the content of a triangular piece of ground, Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor. "
A Treatise of Practical Surveying, ... - Side 182
av Robert Gibson - 1808 - 440 sider
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1795 - 319 sider
...thereof • to that of the Bafe, by a Right Line, and thence compleat the Parallelogram. PROB. PR 0 S. VI. To find the Content of a «Triangular Piece of Ground. Multiply the Bafe by Half the Perpendicular, or the Perpendicular by Half the Bafe ; or take Half the Product of...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1804 - 168 sider
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1808 - 168 sider
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1811 - 508 sider
...the extremity thereof to that of the base by a right line, and thence completing the parallelogram. PROB. VI To find the content of a triangular piece...product of the base into the perpendicular. The reason of this is plain, from cor. 2. theo. 12. eeom. EXAMPLE. PL. 1. Jig. 16. Let ^U^ be a triangular piece...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1814 - 508 sider
...line, and thence completing the parallelogram. PROB. VI. To find the content of a triangular fiiece of ground. Multiply the base by half the perpendicular,...product of the base into the perpendicular. The reason of this is plain, from cor. 2. theo. 12. geom. EXAMPLE. PL. i.Jig. 16. Let ABC be a triangular piece...
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A Treatise on Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1818 - 478 sider
...the extremity thereof to that of the base, by a right line ; and thence complete the parallelogram. PROB. VI. To find the content of a triangular piece...perpendicular. The reason hereof is plain, from cor. 2. theo, \3.. sect. i. EXAMPLE. D Let ABC be a triangular piece of ground, whose longest side or base BC, is...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1821 - 544 sider
...1 : SZ-A : ; DAXAB ; 8. ^ JxVAXJIi=tke area of the parallelogram. Q. /.s I» , . 9 PROB. VI. Tafnd the content of a triangular piece of ground. Multiply...product of the base into the perpendicular. The reason of this is plain, from cor. 2. theo. 12. geom. EXAMPLE. PL. 1. 2ig. 16. Let ABC be a triangular piece...
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A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - 1824 - 434 sider
...are given. RULE. Multiply the base by the perpendicular, and half the product will be the area. Or, multiply the base by half the perpendicular ; or the perpendicular by half the base, and the product will be the area. Aote 1. If double the area of a triangle be divided by one of its...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1825 - 241 sider
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the...
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Elements of Geometry and Trigonometry: With an Easy and Concise System of ...

James Hale - 1829 - 115 sider
...? Ans. 63x28=1764-r-160=11 Acres 4 Rods. PROBLEM III. To find the Area of a Right Angled Triangle. Multiply the Base by half the Perpendicular, or the Perpendicular by half the Base, the Product is the Area; or, multiply the Base and Pe/pendicular together, and half the Product is...
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