The Elements of Euclid, the parts read in the University of Cambridge [book 1-6 and parts of book 11,12] with geometrical problems, by J.W. Colenso1846 |
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Side 6
... draw the straight lines CA , CB , to the points A , B ( Post . 1 ) : ABC shall be an equilateral triangle . BE ... draw a straight line equal to a given straight line . Let A be the given point , and BC the given straight line : it is ...
... draw the straight lines CA , CB , to the points A , B ( Post . 1 ) : ABC shall be an equilateral triangle . BE ... draw a straight line equal to a given straight line . Let A be the given point , and BC the given straight line : it is ...
Side 7
... draw the straight line AB ; and upon it describe the equilateral triangle DAB ( 1. 1 ) , and produce the straight lines DA , DB , to E and F ( Post . 2 ) ; from the centre B , at the distance BC , describe the circle CGH , and from the ...
... draw the straight line AB ; and upon it describe the equilateral triangle DAB ( 1. 1 ) , and produce the straight lines DA , DB , to E and F ( Post . 2 ) ; from the centre B , at the distance BC , describe the circle CGH , and from the ...
Side 14
... draw a straight line at right angles to a given straight line from a given point in the same . Let AB be the given straight line , and C a given point in it it is required to draw from the point C a straight line at right angles to AB ...
... draw a straight line at right angles to a given straight line from a given point in the same . Let AB be the given straight line , and C a given point in it it is required to draw from the point C a straight line at right angles to AB ...
Side 15
... draw BE at right angles to AB : Then , because ABC is a straight line , the angle CBE is equal to the angle EBA ( Def . 10 ) : So also , because ABD is a straight line , the angle DBE is equal to the angle EBA : Therefore the angle DBE ...
... draw BE at right angles to AB : Then , because ABC is a straight line , the angle CBE is equal to the angle EBA ( Def . 10 ) : So also , because ABD is a straight line , the angle DBE is equal to the angle EBA : Therefore the angle DBE ...
Side 16
... drawn from the given point C perpendicu- lar to the given straight line AB . H D GB Because FH is equal to HG , and ... draw BE at right angles to CD ( 1. 11 ) ; then the E D B C DB angles CBE , EBD are two right angles : And , because ...
... drawn from the given point C perpendicu- lar to the given straight line AB . H D GB Because FH is equal to HG , and ... draw BE at right angles to CD ( 1. 11 ) ; then the E D B C DB angles CBE , EBD are two right angles : And , because ...
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The Elements of Euclid, the Parts Read in the University of Cambridge [Book ... Euclides Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
ABCD adjacent angles angle ABC angle ACB angle BAC angle BCD angle EDF angle equal base BC BC is equal centre chord circle ABC circumference cuts the circle diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given straight line gnomon greater ratio inscribed intersection isosceles triangle less Let ABC Let the straight lines be drawn lines drawn meet multiple opposite angles opposite sides parallel to BC parallelogram pentagon perpendicular plane polygon PROB produced proportionals Q.E.D. PROP rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn square of AC straight line &c straight line AB THEOR touches the circle triangle ABC twice the rectangle Wherefore
Populære avsnitt
Side 42 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 4 - Let it be granted that a straight line may be drawn from any one point to any other point.
Side 33 - F, which is the common vertex of the triangles: that is », together with four right angles. Therefore all the angles of the figure, together with four right angles are equal to twice as many right angles as the figure has sides.
Side 62 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Side 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.
Side 58 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Side 146 - ... may be demonstrated from what has been said of the pentagon : and likewise a circle may be inscribed in a given equilateral and equiangular hexagon, and circumscribed about it, by a method like to that used for the pentagon.
Side 194 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Side 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.