The Elements of Euclid for the Use of Schools and CollegesMacmillan, 1872 - 400 sider |
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Resultat 1-5 av 38
Side 24
... reason , the exterior angle CEB of the tri- angle ABE is greater than the angle BAE . But it has been shewn that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC Wherefore , if ...
... reason , the exterior angle CEB of the tri- angle ABE is greater than the angle BAE . But it has been shewn that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC Wherefore , if ...
Side 39
... reason EF is equal to BC ; therefore AD is equal to EF ; [ I. 34 . [ Axiom 1 . therefore the whole , or the remainder , AE is equal to the whole , or the remainder , DF . And AB is equal to DC ; [ Axioms 2 , 3 . [ I. 34 . therefore the ...
... reason EF is equal to BC ; therefore AD is equal to EF ; [ I. 34 . [ Axiom 1 . therefore the whole , or the remainder , AE is equal to the whole , or the remainder , DF . And AB is equal to DC ; [ Axioms 2 , 3 . [ I. 34 . therefore the ...
Side 40
... reason the parallelogram EFGH is equal to the same EBCH . Therefore the parallelogram ABCD is equal to the par- allelogram EFGH . [ Axiom 1 . Wherefore , parallelograms & c . Q.E.D. PROPOSITION 37. THEOREM . Triangles on the same base ...
... reason the parallelogram EFGH is equal to the same EBCH . Therefore the parallelogram ABCD is equal to the par- allelogram EFGH . [ Axiom 1 . Wherefore , parallelograms & c . Q.E.D. PROPOSITION 37. THEOREM . Triangles on the same base ...
Side 45
... reason the triangle KGC is equal to the triangle KFC . Therefore , because the triangle AEK is equal to the tri- angle AHK , and the triangle KGC to the triangle KFC ; the triangle AEK together with the triangle KGC is equal to the ...
... reason the triangle KGC is equal to the triangle KFC . Therefore , because the triangle AEK is equal to the tri- angle AHK , and the triangle KGC to the triangle KFC ; the triangle AEK together with the triangle KGC is equal to the ...
Side 50
... reason , AB and AH are in the same straight line . Now the angle DBC is equal to the angle FBA , for each of them is a right angle . Add to each the angle ABC . [ Axiom 11 . Therefore the whole angle DBA is equal to the whole angle FBC ...
... reason , AB and AH are in the same straight line . Now the angle DBC is equal to the angle FBA , for each of them is a right angle . Add to each the angle ABC . [ Axiom 11 . Therefore the whole angle DBA is equal to the whole angle FBC ...
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Vanlige uttrykk og setninger
ABCD AC is equal angle ABC angle ACB angle BAC angle EDF angles equal Axiom base BC bisects the angle centre chord circle ABC circle described circumference Construction Corollary describe a circle diameter double draw a straight equal angles equal to F equiangular equilateral equimultiples Euclid Euclid's Elements exterior angle given circle given point given straight line gnomon Hypothesis inscribed intersect isosceles triangle less Let ABC magnitudes middle point multiple opposite angles opposite sides parallelogram perpendicular plane polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION quadrilateral radius rectangle contained rectilineal figure remaining angle rhombus right angles right-angled triangle segment shew shewn side BC square on AC straight line &c straight line drawn tangent THEOREM touches the circle triangle ABC triangle DEF twice the rectangle vertex Wherefore