 | Thomas Keith - 1817 - 306 sider
...the result will be the .solidity. RULE II. To three times the square of the radius of the segment,s base, add the square of its height ; multiply this...sum by the height, and the product by •5236, the result will be the solidity. Example 1. Let ABD o be the segment of a sphere, of which the diameter... | |
 | William Hawney - 1820 - 336 sider
...the suliciitv., It RULE II. To three times the square of the radius of the segment's base, add t!ic square of its height ; multiply this sum by the height, and the product by .5:236, and the last product will be the sulidity . EXAMPLES. 1. Let ABCD be the frustum of a sphere ; suppose... | |
 | Ireland commissioners of nat. educ - 1834 - 370 sider
...(-5236 tP h) - (d2 h — 3 ii h2 + 2 h ' ) X -5236 = (3;/A-2A')Х-5236=;(3<*А-2А,)Х '5236 = (3 rf by the height, and the product by -5236, the last...intercepted between the polar circle and the pole 23| degrees ; that is, AD = 23 | degrees, supposing AB to represent the polar circle. By Rule I. As... | |
 | Almon Ticknor - 1849 - 156 sider
...segment with one base. RULE. — To 3 times the square of the radius of the base add the square of the height. Multiply this sum by the height, and the product by -5236 ; the result will be the solidity of the segment. 1. What is the solidity of the segment ABD, the height... | |
 | Charles Haynes Haswell - 1858 - 350 sider
...Contents of a Segment of a Sphere, Fig. 98. RULE 1. To three times the square of the radius of its base add the square of its height ; multiply this sum by the height, and the product, multiplied by .5236, will give the contents required. Or, (Sr2 + A2) x Ax -5236 =S. 2. From three times... | |
 | Frank Eugene Kidder - 1886 - 640 sider
...roluiiic, of a segment of a Kphere. lin.E 1. — To three times the square of the radius of its base dd the square of its height; multiply this sum by the height, and he product by O.òiìli. Til i. K 2. — From three times the diameter of the sphere subtract wice... | |
 | 1890 - 478 sider
...simple rule for the segments of spheres may serve for such vessels as crystalllzers ; in this case, to three times the square of the radius of the segment's...multiply this sum by the height, and the product by 0-5236, which will give the contents required. Substance. Pounds. Substance. Pounds. Black Ash . .... | |
 | Frank Eugene Kidder - 1892 - 1058 sider
...compute the volunte of a segment of a xphere. RULE 1. — To three times the, square of the radius of its base add the square of its height; multiply this sum by the height, and the product by 0.523(5. RULE 2. — From three times the diameter of the sphere subtract twice the height of the segment;... | |
 | George Edward Davis - 1904 - 560 sider
...Solidity of the Segment of a Sphere. To three times the square of the radius of the base of the segment, add the square of its height, multiply this sum by the height, and the product by 0-5236, which gives the required solidity. The Weight of Iron Spheres. Divide nine times the cube of... | |
 | Frank Eugene Kidder - 1908 - 1760 sider
...compute (he volume of a segment of a sphere. RULE 1 . — To three times the square of the radius of its base add the square of its height; multiply this sum by the height, and the product by 0.5236. RULE 2. — From three times the diameter of the sphere subtract twice the height of the segment;... | |
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Rule 2. From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236. 
