PROP. XIX. THEOR. SIMILAR triangles are to one another in the duplicate ratio of their homologous sides. Let ABC, DEF be similar triangles, having the angle B equal to the angle E, and let AB be to BD, as DE to EF, so that the side BC is homologous to EF (12. def. 5.); the triangle ABC has to the striangle DEF the duplicate ratio of that which BC has to EF. Take BG a third proportional to BC, EF (11. 6.), so that BC is to EF, as EF to BG, and join GA; then, because as AB to BC, so DE to EF, alternately (16. 5.), AB is to DE, as BC to EF: but as BC to EF; so is EF to BG; therefore (11. 5.), as AB to DE, so is EF to BG; wherefore the sides of the triangles ABG, DEF which are about the equal angles, are reciprocally proportional : but triangles which have the sides about two equal angles reciprocally proportional, are equal to one another (15. 6.): therefore the triangle ABG is equal to the triangle DEF: and because as BC is to EF, so EF to BG; and that if three straight Jines be proportionals, the first is said (10. def. 5.) to R G C E have to the third the duplicate ratio of that which it has to the second ; BC therefore has to BG the duplicate ratio of that which BC has to EF: but as BC to BG, so is (1. 6.) the triangle ABC to the triangle ABG. Therefore the triangles ABC has to the triangle ABG the duplicate ratio of that which BC has to EF: but the triangle ABG is equal to the triangle DEF: wherefore also the triangle ABC has to the triangle DEF the duplicate ratio of that which BC has to EF. Therefore, similar triangles, &c. Q. E. D. Cor. From this it is manifest, that if three straight lines be proportionals, as the first is to the third, so is any triangle upon the first to a similar and similarly described triangle upon the second. PROP. XX. THEOR. · Similar polygons may be divided into the same number of similar triangles, having the same ratio to one another that the polygons have: and the polygons have to one another the duplicate ratio of that which their homologous sides have. Let ABCDE, FGHKL be similar polygons, and let AB be the homologous side to FG : the polygons ABCDE, FGHKL may be divided into the same number of similar triangles, whereof each to each has the same ratio which the polygons have; and the polygon ABCDE has to the polygon FGHKL the duplicate ratio of that which the side AB has to the side FG. Join BE, EC, GL, LH: and because the polygon ABCDE is simi. lar to the polygon FGHKL, the angle BAE is equal to the angle GFL (1. def. 6.), and BA is to AE, as GF to FL (1. def. 6.); wherefore because the triangles ABE, FGL, have an angle in one equal to an angle in the other, and their sides about these equal angles proportionals; the triangle ABE is equiangular (6. 6.), and therefore similar to the triangle FGL (4. 6.); wherefore the angle ABE is equal to the angle FGL: and, because the polygons are similar, the whole angle ABC is equal (1. def. 6.) to the whole angle FGH; therefore the remaining angle EBC is equal to the remaining angle LGH: and because the triangles ABE, FGL are similar, EB is to BA, as LG to GF (1. def. 6.); and also, because the polygons are similar, AB is to BC, as FG to GH (1. def. 6.); therefore ex æquali (22. 5.), EB is to BC, as LG to GH; that is, the sides about the equal angles EBC, LGH are proportionals; therefore (22. 5.) the triangle EBC is equiangular to the tri M angle LGH, and similar to it (4. 6.). For the same rea- E son, the triangle ECD likewise is similar to the triangle LKH; therefore the similar po- D C KH lygons ABCDE, FGHKL are divided into the same number of similar triangles. Also these triangles have, each to each, the same ratio which the polygons have to one another, the antecedents being ABE, EBC, ECD, and the consequents FGL, LGH, LHK : and the polygon ABCDE has to the polygon FGHKL the duplicate ratio of that which the side AB has to the homologous side FG. Because the triangle ABE is similar to the triangle FGL, ABE, has to FGL the duplicate ratio (19. 6.) of that which the side BE has to the side GL; for the same reason, the triangle BEC has to GLH the duplicate ratio of that which BE has to GL; therefore, as the triangle ABE to the triangle FGL, so (11. 5.) is the triangle BEC to the triangle GLH. Again, because the triangle EBC is similar to the triangle LGH, EBC has to LGH the duplicate ratio of that which the side EC has to the side LH: for the same reason, the triangle ECD has to the triangle LHK, the duplicate ratio of that which EC has to LH; as therefore the triangle EBC to the triangle LGH, so is (11. 5.) the triangle ECD to the triangle LHK; but it has been proved that the triangle EBC is likewise to the triangle LGH, as the triangle ABE to the triangle FGL. Therefore as the triangle ABE is to the triangle FGL, so is triangle EBC to triangle LGH, and triangle ECD to triangle LHK: and therefore as one of the antecedents to one of the consequents, so are all the antecedents to all the consequents (12. 5.). Wherefore as the triangle ABE to the triangle FGL, so is the polygon ABCDE to the polygon FOTKL; but the triangle ABE has to the triangle FGL, the duplicate ratio of that which the side AB has to the homologous side FG. Therefore also the polygon ABCDE has to the polygon FGHKL the duplicate ratio of that which AB has to the homologous side FG. Wherefore, similar polygons, &c. Q. E. D. Cor. 1. In like manner, it may be proved, that similar four sided figures, or of any number of sides, are one to another in the duplicate ratio of their homologous sides, and it has already been proved in triangles. Therefore, universally, similar rectilineal figures are to one another in the duplicate ratio of their homologous sides. Cor. 2. And if to AB, FG, two of the homologous sides, a third proportional M be taken AB has (10. def. 5,) to M the duplicate ratio of that which AB has to FG: but the four sided figure or polygon upon AB, has to the four sided figure or polygon upon FG likewise the duplicate ratio of that which AB has to FG; therefore, as AB is to M, so is the figure upon AB to the figure upon FG, which was also proved in triangles (Cor. 19. 6.). Therefore, universally, it is manifest, that if three straight lines be proportionals, as the first is to the third, so is any rectilineal figure upon the first to a similar and simiJarly described rectilineal figure upon the second. PROP. XXI. THEOR. Rectilineal figures which are similar to the same rectilineal figures, are also similar to one another. Let each of the rectilineal figures, A, B be similar to the rectilineal figure C; the figure A is similar to the figure B. Because A is similar to C; they are equiangular, and also have their sides about the equal angles proportionals (1. def. 6.).' Again, because B is similar to C, they are equiangular, and have their sides about the equal angles proportionals (1.' def. 6.): therefore the figures A, B are each of them equiangular to C, and have the sides about the equal angles of each of them and of C proportionals. Wherefore the rectilineal figures A and B are equiangular (1. Ax. 1.), and have their sides about the equal angles proportionals (11. 5.). Therefore A is similar (1. def. 6.) to B. Q. E. D. PROP. XXII. THEOR. Ir four straight lines be proportionals, the similar rectilineal figures similarly described upon them shall also be proportionals; and if the similar rectilineal figures similarly described upon has to the polygon FGHKL the dupla t lines shall be AB has to the side FG. Join BE, EC, GL, LH: and beca: lar to the polygon FGHKL, the an: se proportionals, viz. GFL (1. def. 6.), and BA is to AE, a che similar rectilineal fore because the triangles ABE, Ford u upon EF, GH the to an angle in the other, and their ner: the rectilineal proportionals; the triangle ABE ; similar to the triangle FGL (4. 6. 1.; X; and to EF, GH to the angle FGL: and, becall -D, as EF to GH, and angle ABC is equal (1. def. 6.) sure, ex æquali (22. 5.), the remaining angle EBC is ec' .. so is (2 Cor. 20. 6.) the because the triangles ABE, F S EF to 0, so is (2 Cor. GF (1. def. 6.); and also, bes. : therefore, as KAB to BC, as FG to GH (1. def. 6.). BC, as LG to GH; that is, ti VF to NH; the straight LGH are proportionals; the: angular to the tri :X and upon PR describe angle LGH, and si ...ak ind similarly situated to milar to it (4. 6.). For the same rea- E son, the triangle ECD likewise is similar to the triangle LKH; therefore the similar polygons ABCDE, FGHKL are divided Also these triangl. polygons have to 0. ECD, and the con н PR ABCDE has to the the side AB has tau se because as AB to CD, so is Because the trio ad tre described the similar and to FGL the dupi , and upon EF, PR, in like R; KAB is to LCD, as MF the side GL; fo. sto LCD, as MF to NH: and duplicate ratio (i. gle ABE to the we same ratio to each of the two triangle GLH, the another : they are also similar, triangle LGII. à equal to PR: and because as side EC has to is equal to GH; AB is to CD, has to the tri wat waght lines, &c. Q. E. D. to LH; as ti 5.) the trian ILI THEOR. that the tria: ABE to the s have to one another the ratio triangle FC kilus of their sides. * to triangle the conse ..3 Arallelograms, having the angle (12. 5.). the poly! * Note BCD equal to the angle ECG: the ratio of the parallelogram AC to the parallelogram CF, is the same with the ratio which is compounded of the ratios of their sides. Let BG, CG, be placed in a straight line; therefore DC and CE are also in a straight line (14. 1.); and complete the parallelogram DG; and, taking any straight line K make (12. 6.) as BC to CG, so K to L; and as DC to CE, so make (12. 6.) L to M: therefore the ratios of K to L, and L to M, are the same with the ratios of the sides, viz. of BC to CG, and DC to CE. But the ratio of K to M is that which is said to be compounded (A. def. 5.) of the ratios of K to L, and L to M: wherefore also K has to M the ratio compounded of the ratios of the sides; and because as BC to CG, SO A D H is the parallelogram AC to the parallelogram CH (1. 6.); but as BC to CG, so is K to L; therefore K is (11. 5.) to L, as the e parallelogram AC to the parallelogram GH: again, because as DC to CE, so is the parallelogram CH to the parallelogram CF; but as DC to CE, so is L to M; wherefore L is (11. 5.) to M, as the parallelogram CH to the parallelogram CF: therefore since it has been proved, that as K to L, so is the parallelogram AC to the parallelogram CH; KLM E F and as L to M, so the parallelogram CH to the parallelogram CF; ex æquali (22. 5.), K is to M, as the parallelogram AC to the parallelogram CF: but K has to M the ratio which is compounded of the ratios of the sides; therefore also the parallelogram AC has to the parallelogram CF the ratio which is compounded of the ratios of the sides. Wherefore, equiangular parallelograms, &c. Q. E. D. PROP. XXIV. THEOR. The parallelograms about the diameter of any parallelogram are similar to the whole and to one another. * Let ABCD be a parallelogram, of which the diameter is AC; and EG, HK the parallelograms about the diameter: the parallelograms EG, HK are similar both to the whole parallelogram ABCD, and to one another. Because DC, GF are parallels, the angle ADC is equal (29. 1.) to the angle AGF: for the same reason, because BC, EF are parallels, the angle ABC is equal to the angle AEF: and each of the angles BCD, EFG is equal to the opposite angle DAB (34. 1.), and therefore are equal to one another; wherefore the parallelograms ABCD, AEFG are equiangular; and because the angle ABC is equal to the angle AEF; and the angle BAC common to the two triangles BAC, EAF, they are equiangular to one another ; therefore (4. 6.) as AB to BC, so is AE to EF: and because the * See Note. |