| Robert Simson - 1762 - 466 sider
...parallelograms, &c. Q^ED PROP. XXXVII. THEOR. HPRi ANGLEs upo'n the fame bafe, and between the fame **parallels, are equal to one another. Let the triangles ABC, DBC be upon the** fairie bafe BC and between the fame parallels AD; BC . the triangle ABC is equal to the triangle DBC.... | |
| Popular educator - 1767
...to show. The reader will remember that in Problem XXIV (page 308) it was shown that triangles on the **same base and between the same parallels are equal to one another,** and that triangles on equal bases and between the same parallels are also equal to one another. Now... | |
| Robert Simson - 1775 - 520 sider
...EFGH. Wherefore parallelograms, &c. Q^ED PROP. XXXVII. THEOR.. upon the fame bafe, and between the fame **parallels, are equal' to one another. Let the triangles ABC, DBC be upon the** fame bafe BC and between the fame parallels -rx A Tl AD, BC: The triangle ABC *i. AA* is equal to the... | |
| Alexander Ingram - 1799 - 351 sider
...PROP. B BooK I. PROP. XXXVII. THEOR. See M. rripviANGLES upon the fame bafe, and between the JL fame **parallels, are equal to one another. Let the triangles ABC, DBC be upon the** fame bafe BC, and between the fame parallels AD, BC : The triangle ABC is equal to the triangle DBC.... | |
| Robert Simson - 1804
...parallelograms, &c. Q^ED »• 34. T PROP. XXXVII. THEOR. RIANGLES upon the fame bafe, and between the fame **parallels, are equal to one another, Let the triangles ABC, DBC be upon the** fame bafe BC and between the fame parallelspi A Tl Ti* AD, BC. the triangle ABC iaF4 A AJ -C equal... | |
| Euclid, Robert Simson - 1806 - 518 sider
...divides the paralkio c 4. 1. gram ACDB into two equal parts. QED PROP. XXXV. THEOR. See N. PARALLELOGRAMS **upon the same base, and between the same parallels, are equal to one another.** Sue OH- Let the parallelograms ABCD, EBCF be upon the same base 2dand3d BC, and between the same parallels... | |
| Euclid - 1810 - 518 sider
...same EBCH : therefore also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. QED **PROP. XXXVII. THEOR. TRIANGLES upon the same base,...the triangles ABC, DBC be upon the same base BC, and** ketween the same parallels p » , AD, BC : the triangle ABC B equal to the triangle DBC. Produce AD... | |
| John Mason Good, Olinthus Gilbert Gregory - 1813
...diameter bisects them, that is, divides them in two equal parts. Prop. XXXV. Theor. Parallelograms **upon the same base and between the same parallels, are equal to one another.** Prop. XXXVI. Theor. Parallelograms upon equal basis, and between the same parallels, are equal to one... | |
| Euclides - 1814
...same EBCH : Therefore also the parallelogram ABCD is equal to EFGH. Wherefore parallelograms,"&c. QED **PROP. XXXVII. THEOR. TRIANGLES upon the same base,...DBC, be upon the same base BC, and between the same** r' parallels AD, BC : The triangle ABC is equal to the triangle DBC. through B draw3 BE pa- ^ ^ Produce... | |
| Euclides - 1816 - 528 sider
...i divides the parallelogram ACDB into two equal" parts. PROP. XXXV. THEOR. , s«eN. PARALLELOGRAMS **upon the same base, and between the same parallels, are equal to one another.** See the ad Let the parallelograms ABCD, EBCF be upon the same and 3d fi. base BC, and between the same... | |
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