 | Charles Vyse - 1806 - 342 sider
...7"", by 8 Feet, 6', 7". (I2j Multiply 46 Feet, 6 In. 8', 4'", by 6 Feet, 4 In.8', &". t PROBLEM II. To find the Area of a Parallelogram, whether it be a Square, a Rectangle, a Rhombus, or a Rhomboides. RULE. Multiply the Length by the Height or perpendicular Breadth, and the Product will... | |
 | Samuel Webber - 1808 - 466 sider
...fathom 16i feet. or } . . 5$ yards } 1 pole or rod 40 poles 1 furlong SQJJARE MEASURES. PR0BLEM I. Tojmd the area of a parallelogram ; whether it be a square^ a rectangle, a rhombus, or a rhomboid. RULE.* Multiply the length by the breadth, or a perpendicular height, and the product will be the area.... | |
 | Peter Nicholson - 1809 - 426 sider
...contains the altitude of the square. Hence we have the following rule for any parallelogram whatever. PROBLEM I. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboides. Multiply the length by the perpendicular height, and the product will be the area. EXAMPLK... | |
 | John Gummere - 1814 - 398 sider
...protracting a survey and finding its area by dividing it into triangles and trapeziums. • • - • PROBLEM I. To find the Area of a Parallelogram, whether it be a Square, a Rectangle, a Rhombus, or a Rhomboides. RULE. Multiply the length by the height or perpendicular breadth, and the product will... | |
 | William Jillard Hort - 1822 - 308 sider
...AB, the height of the tower will be found equal to 223-3 lect. MENSURATION OF PLANE FIGURES. Probltm. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. Rule 1. Multiply the length by the perpendicular breadth, and the product will be the area. a. As the... | |
 | John Nicholson - 1825 - 822 sider
...triangles, are to each other, as the squares of their like sides. MENSURATION OF SUPERFICIES. Prol. 1. To find the area of a parallelogram: whether it be...rhombus, or a rhomboid. Multiply the length by the breadth, or perpendicular height, and the product will be the area. Ex. I. To find the area of a square,... | |
 | Peter Nicholson - 1825 - 1046 sider
...altititude of the square. Hence we have the following rule for any parallelogram whatever. Prob. 1. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboïdes. Multiply the length by the perpendicular height, and (he product will be the area. Ex.... | |
 | Zadock Thompson - 1826 - 176 sider
...Hence the area is said to be so many square inches, square feet, •quare yards, or square rods, &c. Problem I. To find the area of a parallelogram- whether it be a iqvare, a rectangle, a rhombus, or a rhomboid. RULE.— Multiply the length by the breadth, or perpendicular... | |
 | John Gummere - 1828 - 404 sider
...of each may be found; and the sum of these areas will be the area of the tract. PROBLEM I. To fold the area of a Parallelogram, whether it be a Square, a Rectangle, a Rhombus, or a Rhomboides. RULE. Multiply the length by the height or perpendicular breadth, and the product will... | |
 | John Bonnycastle - 1829 - 256 sider
...student by observing this rule will generally find his results to agree with those given in the book. , PROBLEM I. To find the area of a parallelogram; whether it be a square, a rectangle, a rhombus, or a rhomboides. RULE.* Multiply the length by the perpendicular height, and the product will be the area.... | |
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PROBLEM I. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboides. 
