 | Bourdon (M., Louis Pierre Marie) - 1831 - 446 sider
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Bourdon (M., Louis Pierre Marie) - 1831 - 326 sider
...dividend by the first term on the left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second... | |
 | Charles Davies - 1835 - 378 sider
...division polynomials we have the following RULE. on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the fast term of the divisor, which gives... | |
 | 1836 - 530 sider
...divide the first term in the dividend by the first in the divisor, and write the result as the first in the quotient ; multiply the divisor by this term, and subtract the product from the di6 a 6s + б Ь3 vidend ; proceed to deal with the remainder, if any, in the same way. 43. By applying... | |
 | 1838 - 372 sider
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the• divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Charles Davies - 1839 - 272 sider
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Andrew Bell (writer on mathematics.) - 1839 - 500 sider
...rest in order. Divide the first term of the dividend by that of the divisor, the result is the first term of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. Consider the remainder as a new dividend, arrange its terms, and proceed as before ; and... | |
 | Charles Davies - 1842 - 368 sider
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | George Roberts Perkins - 1842 - 370 sider
...on. the left of the dividend by thefirst term on the left .of the divisor, the result is the first term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Charles Davies - 1842 - 284 sider
...term on the left of the dividend by the first term on the left of the divisor, the result is ike first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
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... the first term of the quotient ; multiply the• divisor by this term, and subtract the product from the dividend. 
