Elements of Geometry: Being Chiefly a Selection from Playfair's GeometryA. Walker, 1829 - 186 sider |
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Resultat 1-5 av 35
Side 10
... be proportional , the like pow ers or roots of those quantities will be proportional . If A : B :: C : D , then A " : B " :: C " : D " , n being either a whole number or a fraction . 1 Because B C A9 = = D ' B2 10 PROPORTION .
... be proportional , the like pow ers or roots of those quantities will be proportional . If A : B :: C : D , then A " : B " :: C " : D " , n being either a whole number or a fraction . 1 Because B C A9 = = D ' B2 10 PROPORTION .
Side 21
... whole is greater than its part . A. The whole is equal to all its parts taken together . ED . B. It is impossible for the same thing to have , at the same time , two qualities which are inconsistent with each other . ED . Jag jolenoid ...
... whole is greater than its part . A. The whole is equal to all its parts taken together . ED . B. It is impossible for the same thing to have , at the same time , two qualities which are inconsistent with each other . ED . Jag jolenoid ...
Side 24
... whole trian- gle ABC will coincide with the whole triangle DEF , and be equal to it ; and the remaining angles of one triangle will coin- cide with the remaining angles of the other , and be equal to them , namely , the angle B to E ...
... whole trian- gle ABC will coincide with the whole triangle DEF , and be equal to it ; and the remaining angles of one triangle will coin- cide with the remaining angles of the other , and be equal to them , namely , the angle B to E ...
Side 29
... whole angle BAC is equal to the whole angle BGC . But the angle BGC is , by hypothesis , equal to the angle EDF ; therefore also the angle BAC is equal to EDF . Hence the triangles ABC , DEF are equal in all re- spects ( 4. 1 ...
... whole angle BAC is equal to the whole angle BGC . But the angle BGC is , by hypothesis , equal to the angle EDF ; therefore also the angle BAC is equal to EDF . Hence the triangles ABC , DEF are equal in all re- spects ( 4. 1 ...
Side 43
... whole exterior angle ACD is equal to the two interior and opposite_angles A and B together . Therefore , if any side & c . Q. E. D. Cor . The difference between the exterior angle and either of the interior and opposite angles is equal ...
... whole exterior angle ACD is equal to the two interior and opposite_angles A and B together . Therefore , if any side & c . Q. E. D. Cor . The difference between the exterior angle and either of the interior and opposite angles is equal ...
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Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Ingen forhåndsvisning tilgjengelig - 2023 |
Vanlige uttrykk og setninger
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Populære avsnitt
Side 36 - Any two sides of a triangle are together greater than the third side.
Side 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Side 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Side 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Side 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Side 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Side 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Side 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Side 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.