| James Hodgson - 1723
...the Angle с the other Extream ; wherefore, &c, as was to be proved. Rule i. The Rectangle under the **Radius and the Sine of the Middle Part, is equal to the** Produft of the Co-fines of the Extreams Disjunct, thus if the Complement of ac be taken for the Middle... | |
| Euclid, John Keill - 1733 - 393 sider
...Part. Thefe Things premifed. RULE I. In any right-angled fpherical Triangle, the ReBangle under the **Radius, and the Sine of the middle Part, is equal to the** Reftangle under the Iangents of the adjacent Parts, RULE RULE II. Ibe ReEf angle under the Radius,... | |
| John Keill - 1782 - 399 sider
...Part. Thcfc Things premifed, RULE I. In any Right-angled Spherical Triangle, the Re£langle under the **Radius, and the Sine of the middle Part, is equal to the** ReSlangle under the Tangents of the adjactnt Parts. RULE \ RULE II. Reffangle under the Radius, and... | |
| 1801
...sufficient for the solutions of all the cases of right-angled spherical triangles. THEOREM VII. The product **of radius and the sine of the middle part is equal to the** product of the tangents of the conjunct extremes, or to that of the cosines of the disjunct extremes.*... | |
| Euclid, Robert Simson - 1806 - 518 sider
...rectangle contained by the tangents o' the adjacent parts. RULE IT. The rectangle contained by the **radius, and the sine of the middle part is equal to the rectangle** contained by the co-sines of the opposite parts. These rules are demonstrated in the following manner:... | |
| Samuel Webber - 1808
...sufficient for the solutions of all the cases of right.angled spheric triangles. THEOREM VII. . The product **of radius and the sine of the middle part is equal to** tht- product of the tangents* of the adjacent extremes, or to that of the cosines of the apposite extremes.f... | |
| Euclid - 1810 - 518 sider
...angled spherical triangles are resolved with the greatest ease. RULE I. The rectangle contained by the **radius and the sine of the middle part, is equal to the** rectwpgle contained by the tangents of the adjaeent parts. '/ RULE II. The rectangle contained by the... | |
| Francis Nichols - 1811 - 128 sider
...in the following proposition. 100. In a right-angled spherical triangle, the rectan* gle under the **radius and the sine of the middle part is equal to the rectangle** under the tangents of the adjacent parts, or to the rectangle under the cosines of the opposite parts.... | |
| Euclides - 1816 - 528 sider
...angled spherics! triangles are resolved with the greatest ease. RULE I. The rectangle contained by the **radius and the sine of the middle part, is equal to the rectangle** contained by the tangents of the adjacent parts. RULE II. The rectangle contained by the radius and... | |
| John Playfair - 1819 - 333 sider
...contained in the following " * PROPOSITION. In a right angled spherical triangle, the rectangle under the **radius and the sine of the middle part, is equal to the** rettangle under the tangents of the adjacent parts ; or to the rectangle under the cosines of the opposite,... | |
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