## Trigonometry, Plane and Spherical: With the Construction and Application of Logarithms |

### Inni boken

Resultat 1-5 av 5

Side 2

... the other: Thus the Right-line BE is the Chord, or Subtense, of the Arch BAE or

BDE. 6. The Sine, or Right-sine, of an Arch, is a Right-line drawn from one

Extremity of the Arch, perpendicular to the

Extremity.

... the other: Thus the Right-line BE is the Chord, or Subtense, of the Arch BAE or

BDE. 6. The Sine, or Right-sine, of an Arch, is a Right-line drawn from one

Extremity of the Arch, perpendicular to the

**Diameter**passing thro' the otherExtremity.

Side 22

that the Sečtion of two Great-Circles (as it passes thro' the Center) will be a

interse&t each other in two Points at the Distance of a Semicircle, or 18o Degrees

. 2.

that the Sečtion of two Great-Circles (as it passes thro' the Center) will be a

**Diameter**of the Sphere ; and consequently, that their Peripheries will alwaysinterse&t each other in two Points at the Distance of a Semicircle, or 18o Degrees

. 2.

Side 24

o making an Angle DOE, measured by the Arch ED; the Plane DOE being

supposed perpendicular to the

of the proposed Triangle, BC the Perpendicular, AC the W. and BAC (or DAE =

DE ...

o making an Angle DOE, measured by the Arch ED; the Plane DOE being

supposed perpendicular to the

**Diameter**AL, at the Center O. Let A B be the Baseof the proposed Triangle, BC the Perpendicular, AC the W. and BAC (or DAE =

DE ...

Side 51

... I. The Sine, Cosine, or versed Sine of an Arch being given, to find the Sine and

Co-one, &c. of half that Arch. E 2 From i E From the two Ex- tremes of the

... I. The Sine, Cosine, or versed Sine of an Arch being given, to find the Sine and

Co-one, &c. of half that Arch. E 2 From i E From the two Ex- tremes of the

**Diameter**7%e2%plication of Logarithms, 51. Side 63

Let HG,perpendicular to AB, be the

Triangle, and let HD and Ha be perpendicular to the two Sides of the Triangle ;

also let CF be parallel to A B, and let H A, HB and HC be drawn. Since the

Let HG,perpendicular to AB, be the

**Diameter**of a Circle described about theTriangle, and let HD and Ha be perpendicular to the two Sides of the Triangle ;

also let CF be parallel to A B, and let H A, HB and HC be drawn. Since the

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Trigonometry: Plane and Spherical; with the Construction and Application of ... Uten tilgangsbegrensning - 1799 |

Trigonometry, Plane and Spherical;: With the Construction and ..., Volum 2 Thomas Simpson Uten tilgangsbegrensning - 1765 |

Trigonometry, Plane and Spherical: With the Construction and Application of ... Thomas Simpson Uten tilgangsbegrensning - 1799 |

### Vanlige uttrykk og setninger

adjacent Angle alſo known Arch Baſe becauſe Caſe Chord Circle Co-fine AC Co-ſ Co-tang common Logarithm conſequently Demonſtration Diameter equal to Half Exceſs find the Sine firſt garithms given gles Great-Circles half the Difference Half the Sum half the vertical hyperbolic Logarithm Hypothenuſe L L A R Y laſt leſs likewiſe manifeſt Number oppoſite Angle pendicular perpendicular plane Triangle ABC poſed Produćt Progreſſion Prop propoſed Propoſition Radius reaſon Rečiangle reſpectively right-angled ſpherical Triangle Right-line Ro L L A R ſaid ſame Secant ſecond ſee ſhall Sides AC ſince Sine BCD ſpherical Triangle ABC ſubtracted ſuppoſed T H E o R E M Tang Tangent of Half Theor Theorem theſe thoſe uſeful verſed Sine vertical Angle whence whoſe

### Populære avsnitt

Side 1 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees; and each degree into 60 minutes, each minute into 60 seconds, and so on.

Side 3 - Canon, is a table showing the length of the sine, tangent, and secant, to every degree and minute of the quadrant, with respect to the radius, which is expressed by unity or 1, with any number of ciphers.

Side 6 - In every plane triangle, it will be, as the sum of any two sides is to their difference...

Side 41 - The sum of the logarithms of any two numbers is equal to the logarithm of their product. Therefore, the addition of logarithms corresponds to the multiplication of their numbers.

Side 13 - If the sine of the mean of three equidifferent arcs' dius being unity) be multiplied into twice the cosine of the common difference, and the sine of either extreme be deducted from the product, the remainder will be the sine of the other extreme. (B.) The sine of any arc above 60°, is equal to the sine of another arc as much below 60°, together with the sine of its excess above 60°. Remark. From this latter proposition, the sines below 60° being known, those of arcs above 60° are determinable...

Side 31 - ... is the tangent of half the vertical angle to the tangent of the angle which the perpendicular CD makes with the line CF, bisecting the vertical angle.

Side 73 - BD, is to their Difference ; fo is the Tangent of half the Sum of the Angles BDC and BCD, to the Tangent of half their Difference.

Side 28 - As the sum of the sines of two unequal arches is to their difference, so is the tangent of half the sum of those arches to the tangent of half their difference : and as the sum...

Side 68 - In any right lined triangle, having two unequal sides ; as the less of those sides is to the greater, so is radius to the tangent of an angle ; and as radius is to the tangent of the excess of...