 | Adrien Marie Legendre - 1822 - 394 sider
...equal. In the same manner it may be shewn, that B is equal to E, and C to F. PROPOSITION XII. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. LET the side AB be equal to AC, the angle C will be equal to B. Join A the vertex, and D the middle point... | |
 | Adrien Marie Legendre - 1836 - 394 sider
...thus, the equal angles D and A, lie opposite the equal sides EF and BC. . PROPOSITION XI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. Let the side BA be equal to the side AC ; then will the angle C be equal to the angle B. For, join the... | |
 | Benjamin Peirce - 1837 - 216 sider
...eqnnl to those of another, the other sides and angle are also equal in the two triangles. 55. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Equal Angles of the Isosceles Triangle. Demonstration. In the isosceles triangle ABC (fig. 32), let... | |
 | Nicholas Tillinghast - 1844 - 110 sider
...and DF be equal to AC, EF equal to BC, and the angle at F equal to the angle atC. PROP. VI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. Fig. 6. 11 Let AB, BC, be the equal sides ; then we have to prove that the angle A is equal to £_... | |
 | Benjamin Peirce - 1847 - 204 sider
...equal to those of another, the other sides and angle are also equal in the two triangles. 55. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Proof. In the isosceles triangle ABC (fig. 32), let the equal sides be AB and BC. Equal Angles of the... | |
 | American Association for the Advancement of Science - 1855 - 396 sider
...the observer at 0', then O' M = his latitude, and PM = 90° ; therefore P D' = • J (90° + lat.). In an isosceles triangle the angles opposite the equal sides are equal ; therefore the angle DPC = DOC, but DOC is the azimuth of the object ; therefore the hour-angle of... | |
 | Charles Davies - 1849 - 372 sider
...thus, the equal angles D and A, lie op posite the equal sides EF and BC. • PROPOSITION XI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. For, join the vertex A, and D the middle point of the base BC. Then, the triangles BAD, DAC, will have... | |
 | Charles Davies - 1850 - 218 sider
...coincide with the parts of the triangle DEF, and therefore, the two triangles are equal, THEOREM VI. In an isosceles triangle the angles opposite the equal sides are equal to each other, C Let ABC be an isosceles triangle, having the side AC equal to the side CB : then will... | |
 | Charles Davies - 1850 - 238 sider
...coincide with the parts of the triangle DEF, and therefore, the two triangles are equal. THEOREM VI. •In an isosceles triangle the angles opposite the equal sides are equal to each other, Let ABC be an isosceles triangle, having the side AC equal to the side CB : then will... | |
 | Adrien Marie Legendre - 1852 - 436 sider
...: thus, the equal angles D and A, lie opposite the equal sides EF and BC. PROPOSITION XI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. Let BAC be an isosceles triangle, having the side BA equal to the side A0\ then will the angle 0 be equal... | |
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In an isosceles triangle, the angles opposite the equal sides are equal. 
