A Compleat Treatise of Practical Navigation Demonstrated from It's First Principles: Together with All the Necessary Tables. To which are Added, the Useful Theorems of Mensuration, Surveying, and Gauging; with Their Application to Practice. Written for the Use of the Academy in Tower-StreetJ. Brotherton, 1734 - 414 sider |
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Side vi
... require a particular Volume to explain it . There are indeed two or three Problems ne- ceflary in Practice , which depend on the Refolution of Spherical Triangles ; but for the Solution of thefe , I have laid down fuch clear and fhort ...
... require a particular Volume to explain it . There are indeed two or three Problems ne- ceflary in Practice , which depend on the Refolution of Spherical Triangles ; but for the Solution of thefe , I have laid down fuch clear and fhort ...
Side 22
... required . Cor . 2. Hence , the Legs in a rightangled Tri- angle being given , we may find the Hypothenufe , by taking the Sum of the Squares of the given Legs , and extracting the fquare Root of that Sum . 71 If upon the Line A B there ...
... required . Cor . 2. Hence , the Legs in a rightangled Tri- angle being given , we may find the Hypothenufe , by taking the Sum of the Squares of the given Legs , and extracting the fquare Root of that Sum . 71 If upon the Line A B there ...
Side 25
... required . Example . Let it be required to find the natural Number answering to the Logarithm 2.56229 , by proceeding according to the above Direction I find it to be 365 . Again , if it were required to find the Logarithm of a Number ...
... required . Example . Let it be required to find the natural Number answering to the Logarithm 2.56229 , by proceeding according to the above Direction I find it to be 365 . Again , if it were required to find the Logarithm of a Number ...
Side 26
... required . Example 1. Suppose you were to find the Loga- rithm of 36.5 ; to do this you must first look for the Logarithm of 365 , which is 2.56229 , then because 10 is the Denominator of the decimal Part of the propos'd Number , and ...
... required . Example 1. Suppose you were to find the Loga- rithm of 36.5 ; to do this you must first look for the Logarithm of 365 , which is 2.56229 , then because 10 is the Denominator of the decimal Part of the propos'd Number , and ...
Side 27
... required . Example . Suppofe it were required to find the Number answering to the Logarithm 2.73608 . In order to do this , I look in the Table of Lo- garithms ( without minding the Indices ) for that whofe decimal part is equal , or ...
... required . Example . Suppofe it were required to find the Number answering to the Logarithm 2.73608 . In order to do this , I look in the Table of Lo- garithms ( without minding the Indices ) for that whofe decimal part is equal , or ...
Andre utgaver - Vis alle
A Compleat Treatise of Practical Navigation Demonstrated From It's First ... Archibald Patoun Ingen forhåndsvisning tilgjengelig - 2017 |
A Compleat Treatise of Practical Navigation Demonstrated From It's First ... Archibald Patoun Ingen forhåndsvisning tilgjengelig - 2017 |
A Compleat Treatise of Practical Navigation Demonstrated from It's First ... Archibald Patoun Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
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Populære avsnitt
Side iv - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, etc.
Side iv - A diameter of a circle is a straight line drawn through the center and terminated both ways by the circumference, as AC in Fig.
Side iv - B is an arc, and a right line drawn from one end of an arc to the other is called a chord.
Side 19 - ... 1 and 6, 2 and 5, 3 and 4, 4 and 3, 5 and 2, 6 and 1 , 5 and 6, or 6 and 5.
Side 41 - IN a plain triangle, the fum of any two fides is to their difference, as the tangent of half the fum of the angles at the bafe, to the tangent of half their difference.
Side 39 - In any triangle, the sides are proportional to the sines of the opposite angles, ie. t abc sin A sin B sin C...
Side ix - KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC.
Side 5 - AED, is equal to two right angles ; that is, the sum of the angles...
Side 5 - Thro' C, let CE be drawn parallel to AB ; then since BD cuts the two parallel lines BA, CE ; the angle ECD = B, (by part 3, of the last theo.) and again, since AC cuts the same parallels, the angle ACE = A (by part 2. of the last.) Therefore ECD + ACE = ACD =1 B + AQED THEOREM V. In any triangle ABC, all the three angles taken together are equal to two right angles, viz.
Side 53 - IT is well known, that the longitude of any place is an arch, of the equator, intercepted between the firft meridian and the meridian of that place ; and that this arch is proportional to the quantity of time that the fun requires to move from the one meridian to the other ; which is at the rate of 24 hours for 360 degrees; one hour for 15 degrees; one minute of time for.