A Compleat Treatise of Practical Navigation Demonstrated from It's First Principles: Together with All the Necessary Tables. To which are Added, the Useful Theorems of Mensuration, Surveying, and Gauging; with Their Application to Practice. Written for the Use of the Academy in Tower-StreetJ. Brotherton, 1734 - 414 sider |
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Resultat 1-5 av 63
Side 18
... thro ' the Center and confequently be a Diameter . Cor . 2. From the two laft it follows , that the Sine of any Arch is the half of the Chord of twice the Arc ; for ( fee the foregoing Scheme ) A D is the Sine of the Arc AF , by the ...
... thro ' the Center and confequently be a Diameter . Cor . 2. From the two laft it follows , that the Sine of any Arch is the half of the Chord of twice the Arc ; for ( fee the foregoing Scheme ) A D is the Sine of the Arc AF , by the ...
Side 21
... thro ' the Point A draw AKL perpendicular to the Hypothenufe BC , join AH , AM , DC , and BG ; then it is plain that DB is equal to BA ( by the 54th ) , alfo BH is equal to BC ( by the fame ) ; fo in the two Triangles DBC , ABH the two ...
... thro ' the Point A draw AKL perpendicular to the Hypothenufe BC , join AH , AM , DC , and BG ; then it is plain that DB is equal to BA ( by the 54th ) , alfo BH is equal to BC ( by the fame ) ; fo in the two Triangles DBC , ABH the two ...
Side 34
... thro ' the Theorems of Geome- try , that are neceffary for the Knowledge of Navi- gation ; we fhall next proceed to fome Problems that are useful for the Practice of that Art . Geometrical Problems . Prob . raife a Perpendicular to that ...
... thro ' the Theorems of Geome- try , that are neceffary for the Knowledge of Navi- gation ; we fhall next proceed to fome Problems that are useful for the Practice of that Art . Geometrical Problems . Prob . raife a Perpendicular to that ...
Side 36
... thro ' E and C draw the Diameter ECD meeting the Circle in D ; join D and B , and the right line DB is that required ; for EBD is a right Angle ( by Cor . 4. of 63d ) , Another Way . Upon the point B as a Center , and with any di ...
... thro ' E and C draw the Diameter ECD meeting the Circle in D ; join D and B , and the right line DB is that required ; for EBD is a right Angle ( by Cor . 4. of 63d ) , Another Way . Upon the point B as a Center , and with any di ...
Side 37
... thro ' the point B draw a line BC parallel to AD ; and from A , with any fmall opening of the Compaffes , fet off a Number of e- qual parts ( on the line A D ) lefs by one than the pro- pos'd Number ( here 6. ) , then from B fet off the ...
... thro ' the point B draw a line BC parallel to AD ; and from A , with any fmall opening of the Compaffes , fet off a Number of e- qual parts ( on the line A D ) lefs by one than the pro- pos'd Number ( here 6. ) , then from B fet off the ...
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A Compleat Treatise of Practical Navigation Demonstrated From It's First ... Archibald Patoun Ingen forhåndsvisning tilgjengelig - 2017 |
A Compleat Treatise of Practical Navigation Demonstrated From It's First ... Archibald Patoun Ingen forhåndsvisning tilgjengelig - 2017 |
A Compleat Treatise of Practical Navigation Demonstrated from It's First ... Archibald Patoun Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
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Populære avsnitt
Side iv - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, etc.
Side iv - A diameter of a circle is a straight line drawn through the center and terminated both ways by the circumference, as AC in Fig.
Side iv - B is an arc, and a right line drawn from one end of an arc to the other is called a chord.
Side 19 - ... 1 and 6, 2 and 5, 3 and 4, 4 and 3, 5 and 2, 6 and 1 , 5 and 6, or 6 and 5.
Side 41 - IN a plain triangle, the fum of any two fides is to their difference, as the tangent of half the fum of the angles at the bafe, to the tangent of half their difference.
Side 39 - In any triangle, the sides are proportional to the sines of the opposite angles, ie. t abc sin A sin B sin C...
Side ix - KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC.
Side 5 - AED, is equal to two right angles ; that is, the sum of the angles...
Side 5 - Thro' C, let CE be drawn parallel to AB ; then since BD cuts the two parallel lines BA, CE ; the angle ECD = B, (by part 3, of the last theo.) and again, since AC cuts the same parallels, the angle ACE = A (by part 2. of the last.) Therefore ECD + ACE = ACD =1 B + AQED THEOREM V. In any triangle ABC, all the three angles taken together are equal to two right angles, viz.
Side 53 - IT is well known, that the longitude of any place is an arch, of the equator, intercepted between the firft meridian and the meridian of that place ; and that this arch is proportional to the quantity of time that the fun requires to move from the one meridian to the other ; which is at the rate of 24 hours for 360 degrees; one hour for 15 degrees; one minute of time for.