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Bøker Bok 110 av 20KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the...
" KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. "
A Compleat Treatise of Practical Navigation Demonstrated from It's First ... - Side 22
av Archibald Patoun - 1734 - 414 sider
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1795 - 319 sider
...Sum of the Squares, Plate I. Squares, = BKLH+KCML, the Sum of the two Parallelograms or Square BCMH ; therefore the Sum of the Squares on AB and AC is equal to the Square on BC. Q^ ED Cor. i. Hence the Hypothenufe of a rightangled Triangle may be found by having the Legs ; thus,...
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1806 - 452 sider
...ACGF the sum of the Plate I. squares = BELH + KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. QED Cor. Hence the hypothenuse of a right-angled triangle may be found by having the legs ; thus, the...
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A Treatise of Practical Surveying, ...

Robert Gibson - 1808 - 440 sider
...ACGF the sum of the Plate I. squares, = BKLH+KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. -QED Cor. 1. Hence the hypothenuse of a rightangled triangle may be found by having the legs ; thus,...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1811 - 508 sider
...So AB DE + ACGF the sum of the &quvces=BKLH+KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. 2. ED Cor. 1. Hence the hypothenuse of a right-angled triangle may Its found by having the sides ;...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1814 - 508 sider
...ABDE+ACGFûie sum of the squares= BKLH + KCML, the sum of the two parallelograms or square BCMH ; thei'efore the sum of the squares on AB and AC is equal to tiie square on BC. QED Cor. 1. Hence the hypothenuse of a right-angled triangle may be found by having...
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The New American Practical Navigator: Being an Epitome of Navigation ...

Nathaniel Bowditch - 1826 - 617 sider
...parallelograms BKLH and KCML : the sum of these parallelograms is equal to the square BCMH, therefore sum of the squares on AB and AC is equal to the square on BC. Cor. Hence in any right angled triangle, if we have the hypotenuse one of the legs, we may easily find the...
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The New American Practical Navigator: Being an Epitome of Navigation ...

Nathaniel Bowditch - 1826 - 617 sider
...BKLH and KCML ; but lhe. sum of these parallelograms is equal to the square BCMH, therefore the iyirn of the squares on AB and AC is equal to the square on BC. Cor. Hence in any right angled triangle, if we have the hypotenuse and one of the legs, we may easily find...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1832 - 348 sider
...ABDE+ACGF the sum of the squares —BKLH-\-KCML, the sum of the two parallelograms or square BCMH; therefore the sum of the squares on AB and AC is equal to the square on BC. QED* . Cor. 1. Hence the hypothenuse of a right-angled triangle may be found by having the sides :...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson, James Ryan - 1839 - 412 sider
...the squares =BKLH+KCML, the sum of the two parallelograms or square BCMH; therefore the sum of ihe squares on AB and AC is equal to the square on BC. QED* Cor. 1. Hence the hypothenuso of a right-angled triangle may be found by having the sides i thus,...
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The New American Practical Navigator; Being an Epitome of Navigation ...

Nathaniel Bowditch - 1846 - 451 sider
...JMrallelograms BKLH and KCML; but the sum of these parallelograms is equal to the square ВСЛ1Н ; therefore the sum of the squares on AB and AC is equal to the square on BC. Cor. Hence, in any right-angled triangle, if we have the hypotenuse and one of the legs, we may easily find...
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