The New Practical Builder and Workman's Companion, Containing a Full Display and Elucidation of the Most Recent and Skilful Methods Pursued by Architects and Artificers ... Including, Also, New Treatises on Geometry ..., a Summary of the Art of Building ..., an Extensive Glossary of the Technical Terms ..., and The Theory and Practice of the Five Orders, as Employed in Decorative ArchitectureThomas Kelly, 1823 - 596 sider |
Inni boken
Resultat 1-5 av 18
Side 13
... CHORD of a circle is a straight line , drawn through the circle , and terminated by the circumference . Thus the line ab , fig . 28 , is a chord ; and a b , fig . 27 , is a chord passing through the centre . 38. A SEMI - CIRCLE is the ...
... CHORD of a circle is a straight line , drawn through the circle , and terminated by the circumference . Thus the line ab , fig . 28 , is a chord ; and a b , fig . 27 , is a chord passing through the centre . 38. A SEMI - CIRCLE is the ...
Side 14
... chord , and the part of the circumference intercepted by the chord . Thus , ab c , figures 28 and 29 , are segments ; and fig . 30 , though a semi - circle , is still a segment , terminated by the diameter , instead of a lesser chord ...
... chord , and the part of the circumference intercepted by the chord . Thus , ab c , figures 28 and 29 , are segments ; and fig . 30 , though a semi - circle , is still a segment , terminated by the diameter , instead of a lesser chord ...
Side 30
... chord which joins the points of intersection , and shall divide it into two equal parts . CH B For the line AB , which joins the points of intersection , being a common chord to the two circles ; if , through the middle of this chord ...
... chord which joins the points of intersection , and shall divide it into two equal parts . CH B For the line AB , which joins the points of intersection , being a common chord to the two circles ; if , through the middle of this chord ...
Side 33
... chord AB , drawn from the point of contact , is equal to the angle AGB in the alternate segment . Let the diameter ACF be drawn , and GF be joined ; and , because the angles FGA , FAE , are right - angles ( theorems 37 , 30 ) , and of ...
... chord AB , drawn from the point of contact , is equal to the angle AGB in the alternate segment . Let the diameter ACF be drawn , and GF be joined ; and , because the angles FGA , FAE , are right - angles ( theorems 37 , 30 ) , and of ...
Side 60
... chord , is equal to the rectangle of the two distances from the point of intersection to each extremity of the other chord . Let AB and CD be two chords , and let them be produced to meet in O ; OA × OB = OD × OC . For , join AC and BD ...
... chord , is equal to the rectangle of the two distances from the point of intersection to each extremity of the other chord . Let AB and CD be two chords , and let them be produced to meet in O ; OA × OB = OD × OC . For , join AC and BD ...
Vanlige uttrykk og setninger
ABCD abscissa adjacent angles altitude angle ABD annular vault axes axis major base bisect called centre chord circle circumference cone conic section conjugate contains COROLLARY 1.-Hence cutting cylinder describe a semi-circle describe an arc diameter distance divide draw a curve draw lines draw the lines edge ellipse Engraved equal angles equal to DF equation equiangular figure GEOMETRY given straight line greater groin homologous sides hyperbola intersection join joist latus rectum less Let ABC line of section meet multiplying Nicholson opposite sides ordinate parallel to BC parallelogram perpendicular PLATE points of section polygon PROBLEM produced proportionals quantity radius rectangle regular polygon ribs right angles roof segment similar triangles square straight edge subtracted surface Symns tangent THEOREM timber transverse axis triangle ABC vault vertex wherefore
Populære avsnitt
Side 27 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 20 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side 51 - The area of a parallelogram is equal to the product of its base and its height: A = bx h.
Side 15 - AXIOMS. 1. Things which are equal to the same thing are equal to one another. 2. If equals be added to equals, the wholes are equal. 3. If equals be taken from equals, the remainders are equal.
Side 15 - LET it be granted that a straight line may be drawn from any one point to any other point.
Side 28 - ... angles of another, the third angles will also be equal, and the two triangles will be mutually equiangular. Cor.
Side 81 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Side 80 - The sine of an arc is a straight line drawn from one extremity of the arc perpendicular to the radius passing through the other extremity. The tangent of an arc is a straight line touching the arc at one extremity, and limited by the radius produced through the other extremity.
Side 28 - After remarking that the mathematician positively knows that the sum of the three angles of a triangle is equal to two right angles...
Side 22 - The perpendicular is the shortest line that can be drawn from a point to a straight line.