A treatise on plane co-ordinate geometryMacmillan & Company, 1855 |
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Side 2
... perpendicular to OX as the axis of y . Also let and be the polar co - ordinates of P. If we draw from P a perpendicular on OX , we see that x = r cos 0 , and y = r sin 0 . These equations connect the rectangular and polar co - ordi ...
... perpendicular to OX as the axis of y . Also let and be the polar co - ordinates of P. If we draw from P a perpendicular on OX , we see that x = r cos 0 , and y = r sin 0 . These equations connect the rectangular and polar co - ordi ...
Side 4
... perpendicular to OX as the axis of y . Also let @ and r be the polar co - ordinates of P. If we draw from P a perpendicular on OX , we see that x = r cos 0 , and = r sin 0 . y = These equations connect the rectangular and polar co ...
... perpendicular to OX as the axis of y . Also let @ and r be the polar co - ordinates of P. If we draw from P a perpendicular on OX , we see that x = r cos 0 , and = r sin 0 . y = These equations connect the rectangular and polar co ...
Side 14
... perpendicular from the origin , and the inclination of this perpendicular to the axis . B P M X Let OQ be the perpendicular from the origin on a 16 EQUATION IN TERMS OF THE PERPENDICULAR .
... perpendicular from the origin , and the inclination of this perpendicular to the axis . B P M X Let OQ be the perpendicular from the origin on a 16 EQUATION IN TERMS OF THE PERPENDICULAR .
Side 15
Isaac Todhunter. Let OQ be the perpendicular from the origin on a line AB . Take any point P in the line ; draw PM per- pendicular to OA , MN perpendicular to OQ , and PR perpen- dicular to MN . Suppose OQ = p , and the angle QOA = a ...
Isaac Todhunter. Let OQ be the perpendicular from the origin on a line AB . Take any point P in the line ; draw PM per- pendicular to OA , MN perpendicular to OQ , and PR perpen- dicular to MN . Suppose OQ = p , and the angle QOA = a ...
Side 20
... perpendicular from the origin , and the inclinations of the per- pendicular to the axes . In the figure of Art . 20 , if we suppose QOA = a , we have QOB = w - a ; denote this by B ; then OQ = a cosa ; OQ = b cos ẞ ; :: a = .. b ...
... perpendicular from the origin , and the inclinations of the per- pendicular to the axes . In the figure of Art . 20 , if we suppose QOA = a , we have QOB = w - a ; denote this by B ; then OQ = a cosa ; OQ = b cos ẞ ; :: a = .. b ...
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a² sin² a²b² abscissa asymptotes ax² axes axis of x b2 a² b²x² centre chord of contact circle conic section conjugate diameters conjugate hyperbola constant cos² cy² denote directrix distance draw PM ellipse equa equal equation y² external point find the equation find the locus fixed point focal chord focus given point given straight line Hence the equation inclined latus rectum Let the equation line drawn line joining line which passes major axis meets the curve middle point negative ordinate origin of co-ordinates parabola perpendicular point h point of intersection polar co-ordinates polar equation positive preceding article radical axis radius ratio rectangular respectively right angles second degree shew shewn sides Similarly straight line passing suppose tangent tangents are drawn tion triangle vertex x₁ x²² y₁
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