 | Alexander Malcolm - 1730 - 702 sider
...fliewn that</x«— -i=s/— -л. and dividing equally by » — i, it is</= *. Ж *^~ I 2. For ti multiply the Sum of the Extremes by the Number of Terms, and take half of the Produo, it's the Sum : Thus *= *"HX*. E*a*,fk: - = 3./=iy.» = 7. then is /==6, —... | |
 | 1801 - 446 sider
...term, the last term, and the number of terms behtg given, to find the sum of all the terms. RULE.* Multiply the sum of the extremes by the number of...and half the product will be the answer. EXAMPLES. * Suppose another series of the same kind with the given one be placed under it in an inverse order... | |
 | Samuel Webber - 1808 - 466 sider
...Thejirst term, the last term, and the number of terms beinggiven, to jind the sum of all the terms, Multiply the sum of the extremes by the number of...answer. EXAMPLES. 1. The first term of an arithmetical progrrssion is 2, the last term 53, and the number of terms 18 ; required the sum of the series. *... | |
 | Nicolas Pike - 1808 - 470 sider
...term, the last term, and the number of terms being given, tojind the sum of all the terms. RuLE.f — Multiply the sum of the extremes by the number of terms, and half the producl will be the answer. EXAMPLES. • The difference of the firft and laft terms evidently (hews... | |
 | Nicolas Pike - 1809 - 312 sider
...term, and the number of terms being gi-oent to fnd the fum of all ths terms, RULE. Multiply the fum of the extremes by the number of terms, and half the product will be the anfwer. EXAMPLES. i. The extremes of an arithmetical feries are 3 and 39, and the number of terms i... | |
 | 1811 - 210 sider
...difference, and ,to the product add the first teim, the sum is the last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum qf all the terms. f EXAMPLES. •I. The first term 01 a certain series in anumicucoi progression... | |
 | Nathan Daboll - 1813 - 244 sider
...process, and are here oniii* "A . — Multiply the sum of the exmmcs by the numbei i t.ms, and liall' the product will be the answer. EXAMPLES. 1. The first term of an arithmetical series is 3, the las' term 23, and the number of terms 1 1 ; required the sum of the series. 23+3=26 sum of the extremes.... | |
 | Nathan Daboll - 1815 - 250 sider
...Problems ; but mast of them are best understood by an algebraic process, iand »re here omiti.".' t RULE. Multiply the sum of the extremes by the number of terms, and half the product wiH be the answer. EXAMPLE8. ). The first term of an arithmetical series is 3, the last term 23, and... | |
 | Nathan Daboll - 1817 - 252 sider
...Problems ; but most of them. are best understood by an algebraic process, md are here omitted. :, RULE. Multiply the sum of the extremes by the number of...series is 3, the last term 23, and the number of terms 11 ; required the sum of the series. 23-|-3=26 sum of the extremes. Then 26X11 -r-2= 143 the Answer.... | |
 | 1817 - 214 sider
...difference, and to the product add the first term, the sum is the last term. > 2. Multiply the sum ef the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAMPLES. 1 . The first term of a certain series in arithmetical pro gression... | |
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Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical series is 3, the last term 23, and the number of terms 1 1 ; required the sum of the series. 
