Elements of geometry, containing the first two (third and fourth) books of Euclid, with exercises and notes, by J.H. Smith, Del 11871 |
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Resultat 1-5 av 18
Side 13
... AC = DF , and △ BAC = △ EDF . Then must BC = EF and △ ABC = ^ DEF , and the other Ls , to which the equal sides are opposite , must be equal , that is , LABC = L DEF and LACB = L DFE . For , if ABC be applied to △ DEF , so that A ...
... AC = DF , and △ BAC = △ EDF . Then must BC = EF and △ ABC = ^ DEF , and the other Ls , to which the equal sides are opposite , must be equal , that is , LABC = L DEF and LACB = L DFE . For , if ABC be applied to △ DEF , so that A ...
Side 17
... AC ÷ DF , and △ BAC = △ EDF . 4 For if a DEF be applied to △ ABC , so that E coincides with B , and EF falls on BC ; then and EF - BC , . F will coincide with C ' ; DEF = LABC , .. ED will fall on BA ; .. D will fall on BA or BA ...
... AC ÷ DF , and △ BAC = △ EDF . 4 For if a DEF be applied to △ ABC , so that E coincides with B , and EF falls on BC ; then and EF - BC , . F will coincide with C ' ; DEF = LABC , .. ED will fall on BA ; .. D will fall on BA or BA ...
Side 18
... AC = DF , and BC = EF . Then must the triangles be equal in all respects . Imagine the DEF to be turned over and applied to the △ ABC , in such a way that EF coincides with BC , and the vertex D falls on the side of BC opposite to the ...
... AC = DF , and BC = EF . Then must the triangles be equal in all respects . Imagine the DEF to be turned over and applied to the △ ABC , in such a way that EF coincides with BC , and the vertex D falls on the side of BC opposite to the ...
Side 36
... DF . In AB , produced if necessary , make AG = DE . In AC , produced if necessary , make AH - EF . In HC , produced if necessary , make HKFD . With centre A , and distance AG , describe With centre H , and distance HK , describe LKM ...
... DF . In AB , produced if necessary , make AG = DE . In AC , produced if necessary , make AH - EF . In HC , produced if necessary , make HKFD . With centre A , and distance AG , describe With centre H , and distance HK , describe LKM ...
Side 38
... AC = DF , and let BAC be greater than △ EDF . Then must BC be greater than EF . Of the two sides DE , DF let DE be not greater than DF * . At pt . D in st . line ED make △ EDG = ↳ BAC , and make DG = AC or DF , and join EG , GF . I ...
... AC = DF , and let BAC be greater than △ EDF . Then must BC be greater than EF . Of the two sides DE , DF let DE be not greater than DF * . At pt . D in st . line ED make △ EDG = ↳ BAC , and make DG = AC or DF , and join EG , GF . I ...
Andre utgaver - Vis alle
Elements of Geometry, Containing the First Two (Third and Fourth) Books of ... Euclides Ingen forhåndsvisning tilgjengelig - 2016 |
Elements of Geometry, Containing the First Two (Third and Fourth) Books of ... Euclides Ingen forhåndsvisning tilgjengelig - 2018 |
Elements of Geometry, Containing the First Two (Third and Fourth) Books of ... Euclides Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
AB=DE ABCD AC=DF adjacent angles angle contained angles equal angular points base BC centre coincide describe the sq diagonal draw a straight equal angles equal bases equilat equilateral triangle Euclid Geometry given angle given point given st given straight line half a rt hypotenuse interior angles intersect isosceles triangle LABC LADC LAGH Let ABC Let the st lines be drawn magnitude measure meet middle points opposite angles opposite sides parallel straight lines parallelogram perpendicular polygon Postulate PROBLEM produced proved Q. E. D. Ex quadrilateral rectangle contained reqd rhombus right angles Shew shewn sides equal straight line joining straight lines drawn sum of sqq Take any pt THEOREM together=two rt trapezium triangle ABC triangles are equal twice rect twice sq vertex vertical angle
Populære avsnitt
Side 52 - IF a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are equal to two right angles.
Side 69 - The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another.
Side 83 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square of half the line bisected, is equal to the square of the straight line which is made up of the half and the part produced.
Side 17 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 48 - IF a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another; and the exterior angle equal to the interior and opposite upon the same side; and likewise the two interior angles upon the same side together equal to two right angles...
Side 26 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 86 - If a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Side 90 - In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side subtending the obtuse angle is greater than the squares on the sides containing the obtuse angle, by twice the rectangle contained by the side...
Side 106 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line ; it is required to draw a straight line through the point A, parallel to the straight hue BC.
Side 82 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.