The Elements of Euclid; viz. the first six books, together with the eleventh and twelfth. Also the book of Euclid's Data. By R. Simson. To which is added, A treatise on the construction of the trigonometrical canon [by J. Christison] and A concise account of logarithms [by A. Robertson].1834 |
Inni boken
Resultat 1-5 av 100
Side 10
... join DC : therefore , because in the triangles DBC , ACB , DB is equal to AC , and BC common to both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angie DBC is equal to the angle + ACB ; therefore the ...
... join DC : therefore , because in the triangles DBC , ACB , DB is equal to AC , and BC common to both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angie DBC is equal to the angle + ACB ; therefore the ...
Side 12
... join DE , and upon it describe an equilateral triangle DEF ; then join AF : the straight line AF shall bisect the angle BAC . A DA E B F Because AD is equal † to AE , and AF is com- mon to the two triangles DAF , EAF , the two sides DA ...
... join DE , and upon it describe an equilateral triangle DEF ; then join AF : the straight line AF shall bisect the angle BAC . A DA E B F Because AD is equal † to AE , and AF is com- mon to the two triangles DAF , EAF , the two sides DA ...
Side 13
... join FC : the straight line FC , drawn from the given point C , shall be at right angles to the given straight line AB . + Constr . AD E B 8. 1 . Because DC is equal to CE , and FC common to the two triangles DCF , ECF , the two sides ...
... join FC : the straight line FC , drawn from the given point C , shall be at right angles to the given straight line AB . + Constr . AD E B 8. 1 . Because DC is equal to CE , and FC common to the two triangles DCF , ECF , the two sides ...
Side 14
... join CH : the straight line CH , drawn from the given point C , shall be perpendicular to the given straight line AB . Join CF , CG and because FH is equal † to HG , and HC common to the two triangles FHC , GHC , the two sides FH , HC ...
... join CH : the straight line CH , drawn from the given point C , shall be perpendicular to the given straight line AB . Join CF , CG and because FH is equal † to HG , and HC common to the two triangles FHC , GHC , the two sides FH , HC ...
Side 16
... join BE and produce it to F , and make EF equal to BE , and join FC . Because AE is equal † to EC , and BE † to EF ; AE , EB are equal to CE , EF , each to each ; and the angle AEB is equal * to the angle CEF , because they are opposite ...
... join BE and produce it to F , and make EF equal to BE , and join FC . Because AE is equal † to EC , and BE † to EF ; AE , EB are equal to CE , EF , each to each ; and the angle AEB is equal * to the angle CEF , because they are opposite ...
Andre utgaver - Vis alle
The Elements of Euclid; viz. the first six books, together with the eleventh ... Euclides Uten tilgangsbegrensning - 1814 |
Vanlige uttrykk og setninger
ABC is given AC is equal altitude angle ABC angle BAC base BC bisected centre circle ABCD circle EFGH circumference common logarithm cone Constr cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid ex æquali excess fore given angle given in magnitude given in position given in species given magnitude given ratio given straight line gnomon greater join less Let ABC logarithm multiple parallel parallelogram perpendicular point F polygon prism Prop proportionals Q. E. D. PROPOSITION radius ratio of AE rectangle CB rectangle contained rectilineal figure remaining angle right angles segment shewn sides BA similar sine solid angle solid parallelopiped square of AC straight line AB straight line BC tangent THEOR.-If tiple triangle ABC vertex wherefore
Populære avsnitt
Side 32 - To a given straight line, to apply a parallelogram which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle...
Side 138 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 39 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 22 - If a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another...
Side 41 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together •with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced.
Side 5 - If two triangles have two sides of the one equal to two sides of the other, each to each, but the...
Side 38 - IF a straight line be divided into any two parts, the rectangles contained by the whole and each of the parts, are together equal to the square of the whole line. Let the straight line AB be divided...
Side 262 - Again ; the mathematical postulate, that " things which are equal to the same are equal to one another," is similar to the form of the syllogism in logic, which unites things agreeing in the middle term.
Side 89 - PBOR. —To describe an isosceles triangle, having each of the angles at the base, double of the third angle. Take any straight...
Side 165 - Wherefore, in equal circles &c. QED PROPOSITION B. THEOREM If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.