 | Charles Hutton - 1812 - 620 sider
...Ans. 9 the mean required. FBOBLEK PROBLEM V. Tofindttvo Arithmetical Means between Two Given Extremes. SUBTRACT the less extreme from the greater, and divide the difference by 3, so will the quotient be the common difference ; which being continually added to the less extreme,... | |
 | Charles Hutton - 1816 - 610 sider
...Given Terms or Extremes. SUBTR/VCT the less extreme from the greater, and divide the difference by I more than the number of means required to be found,...term, or subtracted from the greatest, will give the terms required. EXAMPLE. To find five arithmetical means between 2 and 14. Here 14 2 6)12 Then by adding... | |
 | Charles Hutton - 1818 - 646 sider
...com. dif. 2 PROBLEM VI. To find any Number of Arithmetical Means between Toco Given Terms or Extremes. SUBTRACT the less extreme from the greater, and divide...term, or subtracted from the greatest, will give the terms required. EXAMPLE. To find five arithmetical means between 2 and 14. Here 14 6) 12 Then by adding... | |
 | Charles Hutton - 1822 - 616 sider
...2) 18 Am. 9 the mean required. PROBLEM V. Tojind two Arithmetical Means between Two Given Extremes. SUBTRACT the less extreme from the greater, and divide the difference by 3, so will the quotient be the common difference ; which being continually added to the less extreme,... | |
 | Charles Hutton - 1831 - 632 sider
...Arithmetical Means between two given Terms or Extremes. SUBTRACT the less extreme from the greater, nnd divide the difference by 1 more than the number of...difference ; then this being added continually to the leust term, or subtracted from the greatest, will give the mean terms required. EXAMPLE. To find five... | |
 | Ira Wanzer - 1831 - 408 sider
...terms or extremes. RULE. — Subtract the Jess term or extreme from the greater ; divide the remainder by 1 more than the number of means required to be found; that is, divide by 2 for 1 mean, by 3 for 2 means, &c., and the quotient will be the common difference... | |
 | Charles Davies - 1838 - 292 sider
...EXAMPLES. 1. The extremes are 4 and 104, and the number of terms 26 : what is the common difference 1 We subtract the less extreme from the greater and divide the difference by one less tkan OPERATION. 104 426 — 1 = 25)100(4 the number of terms. Ans. 4. 2. A man has 8 sons,... | |
 | mrs. Henry Ayres - 1843 - 470 sider
...CASE 4. — To find any number of arithmetical means between two given terms or extremes. liiilc. — Subtract the less extreme from the greater, and divide...difference by 1 more than the number of means required which will give the common difference; and this being added continually to the least term, or sub.... | |
 | mrs. Henry Ayres - 1846 - 400 sider
...CASE IV. — To find any number of Arithmetical means between two given terms or extremes. Rule. — Subtract the less extreme from the greater, and divide...difference by 1 more than the number of means required, which will give the common difference; and this being added continually to the least term, or subtracted... | |
 | Charles Davies - 1846 - 370 sider
...the number of terms 26 : what is the common difference ? OPERATION. 104 4 26 — 1 = 25)100(4 100 We subtract the less extreme from the greater and divide the difference by one less than the number of terms. 2. A man has 8 sons, the youngest is 4 years old and the eldest... | |
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SUBTRACT the less extreme from the greater, and divide the difference by 1 more than the number of means required to be found... 
