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23.

24.

Area of walls = 2 (22 ft. 3 in. + 17 ft. 9 in.) × (12 in. 6 in.)

= 2 (40 × 123) sq. ft. 1000 sq. ft.;

[blocks in formation]

=

ft. 500 ft. 166 yds. 2ft. ;
=
2

and cost at 3d. per foot will be 1500d. = £6 5s.

£6 5s.÷5s. = 25, the number of sq. yards in the carpet;

[blocks in formation]

26.

area of grass plots = (4 × 223 × 18) sq. ft. = 1620 sq. ft.;

.. the number of sq. ft. to be paved

.. number of sq. yds.

=

8064-1620-6444;

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... cost = (716x82) d. = 6086 d.

9

[blocks in formation]

(Required breadth in linear yards × 743) = 943 × 11 ;

[blocks in formation]

=

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yds. = 132 131 yds.

3584 yds.

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sq. ft. 912 sq. in. 81 ft. 9 in. = 153218 sq. ft. ÷ 813 ft.

[blocks in formation]
[blocks in formation]
[blocks in formation]

34.

35.

36.

[blocks in formation]

Content of wall = (60 × 72 × 1) c. ft. = (5 × 15 × 7) c. ft.;

[blocks in formation]

Content of cistern = (183 × 183 × 63) c. ft. = (14× 55 × 3) c. ft.;

.. weight of water (14 x 55 x 3 x 1000) oz. = 64 tons 9cwt. 7 lbs.

=

A cubic rod of brickwork

= (2724 × 1) c. ft., see p. 90 in Arithmetic.

Content of wall

=3

(77 x 16 x 13) c. ft. (77 x 2 x 15) c. ft.;

.. number of rods of brickwork

=

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38.

39.

40.

Area of walls 2 (201 ft. +18) ft. x 10 ft. = 775 sq. ft.,

=

[blocks in formation]

£194s. 9d. gives 80 as the number of square yards in the cloth. Now length x breadth = 80 sq. yds.;

.. 5 breadth x breadth = 80 sq. yds.;

.. breadth x breadth 16 sq. yds.;

[blocks in formation]
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45.

46.

= 2 (165 ft.+ 153) ft. × 123 ft. = (2 × 3212 × 123) sq. ft.

[blocks in formation]

Area of a postage stamp = (1 x ) sq. in.;

.. number of stamps required

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400 x 60 x 5 = 24000 x 5 = 120000.

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