| 1801 - 426 sider
...side of the greater end 18 inches, and that of the less 12 inches ? Ans. 24*681722. PROBLEM IX. To fnd **the solidity of a wedge. RULE. To the length of the edge add twice** J;he length of the back or base, and reserve the sum ; multiply the height of the wedge by the breadth... | |
| David Steel - 1805
...Produces 479.5616 Cubic inches, or 10.2683 cubic feet, the content. PROBLEM 7. To find the Solidity vf **a Wedge, RULE. To the length Of the edge add twice the length of the** back or base, and reserve the sum ; multiply the height of the wedge by the breadth of the base ; then... | |
| Samuel Webber - 1808
...the side of the greater end 18 inches, and that of the less 12 inches ? Ans. 24' 68 1722, PROBLEM IX. **To find the solidity of a -wedge. RULE.* To the length of the edge add twice the length of the** back or base, and reserve the sum ; multiply the height of the * DEMONSTRATION. When the length of... | |
| John Nicholson - 1831
...9131.80 400 456.5792 20 " 9131.5840 Ansr. VOL. II.— 3 I Prob. 9. To find the Solidity of a Wedge. **To the length of the edge add twice the length of the** back or base, and reserve the sum; multiply the height of the wedge by the breadth of the base; then... | |
| William Templeton (engineer.) - 1833
....y/144 x 64 = 96 then 208 + 96 x 24^ 3 cubic inches, and .M728= 1.4074 cubic feet nearly. PROBLEM VI. **To find the Solidity of a Wedge. RULE. — To the...by the height, and by the breadth of the base, and** ^ of the product will be the solidity. edge DE = 10 inches, and perpendicular height r E = 20 inches.... | |
| James Gallier - 1836 - 208 sider
...diameters; this quotient multiplied by .7854, and again by one third of the height, will give the solidity. **To find the Solidity of a Wedge. RULE. — To the length of the edge** of the wedge, add twice the length of the back ; multiply this sum by the height of the wedge, and... | |
| THOMAS P. JONES, M. D. - 1840
...X £ Л =« S. Or, finally 2/ + É xd X * Л = S. which is the common rule usually expressed thus, **•'To the length of the edge, add twice the length of the** back; multiply this sum by the breadth (or thickness) of the back, and then by one sixth of the height... | |
| Franklin Institute (Philadelphia, Pa.) - 1840
...e~x~5 X £ A = S. Or, finally 21 + exd X * Л = S. which is the common rule usually expressed thus, **"To the length of the edge, add twice the length of the** back; multiply this sum by the breadth (or thickness) of the back, and then by one sixth of the height... | |
| 1844
...formula becomes iA = S, or finally xdx iA = S, or = S, which is the common rule usually expressed thus, " **To the length of the edge, add twice the length of the** back ; multiply this sum by the breadth (or thickness) of the back, and then by one sixth of the height... | |
| William Templeton - 1846 - 220 sider
...cubic feet nearly. PROBLEM VII. To find the solidity of a wedae. RULE. — To the length of the wedge **add twice the length of the base ; multiply that sum...the solidity. EXAMPLE.- — Required the content in** cubic inches of the wedge ABC Tl E, whose base ABC = 12 inches long and 4 inches broad, the length... | |
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