 | Robert Simson - 1806 - 546 sider
...join EA, EB. Then, because AF is equal to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, and the base EA is C equal to the base EB ; therefore the angle b8.t. AFE is equal b to the angle BFE:... | |
 | Euclides - 1816 - 588 sider
...join EA, EB. Then, because AF is equal to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, and the base EA is equal to the base EB ; therek 8. 1. fore the angle AFE is equal b to the angle BFE... | |
 | John Playfair - 1819 - 350 sider
...join EA, EB. Then because AF is equal to FB, and FE common to the two triangles AFE, 8FE, there are two sides in the one equal to two sides in the other ; hut the base EA is equal to the base EB ; therefore the angle AFE is equal (8. 1.) to the angle BFE.... | |
 | Peter Nicholson - 1825 - 1046 sider
...join EA, EB. Then because AF is equal to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, and the base EA is equal to the base EB ; therefore the angle AFE is equal (8. 1 .) to the angle BFE.... | |
 | Robert Simson - 1827 - 546 sider
...EB. Then, because AF is equal f to FB, and FE common t Hypto the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, each to each ; and the base EA is equal f to the base EB ; therefore the angle AFE is equal * to the angle BFE: but when a... | |
 | John Radford Young - 1833 - 286 sider
...cos. a will necessarily diminish as cos. A diminishes; that is, a will increase as A increases: hence if two triangles have two sides in the one equal to two sides in the other, but the included angle in the first greater than the included angle in the second, then the third side... | |
 | John Radford Young - 1833 - 308 sider
...cos. a will necessarily diminish as cos. A diminishes; that is, « will increase as A increases: hence if two triangles have two sides in the one equal to two sides in the oilier, but the included angle in the first greater than the included artglt in the second, then the... | |
 | Euclides - 1834 - 518 sider
...join EA, EB. Then, because AF is equal t to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one, equal to two sides in the other, each to each ; and the base EA is equal t to the base EB ; therefore the angle AFE is equal* to the angle BFE : but when a... | |
 | Euclid - 1835 - 540 sider
...join EA, EB. Then, because AF is equal to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, and the base EA is equal to the base EB; therefore the angle AFE is equal" to the angle BFE. But when... | |
 | John Playfair - 1836 - 148 sider
...join EA, EB ; then because AF is equal to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other ; and the base EA is equal to the base EB ; therefore the angle AFE is equal (7. 1.) to the angle BFE... | |
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E the centre of the circle, and join EA, EB. Then, because AF is equal to FB, and FE common to the two triangles AFE, BFE, there are two sides in the one, equal to two sides in the other, and the base EA is equal to the base EB; therefore the angle AFE... 
