Elements of AlgebraA. S. Barnes, 1838 - 355 sider |
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Resultat 1-5 av 13
Side viii
... Decimal Fractions , 197-199 199-202 · 202-206 206-209 209 209-213 213-215 • • 215-218 • • 218 219 220 221-224 224-227 Formation of Powers and Extraction of Roots , Any Root of a Decimal Fraction , Of Monomials - Of Polynomials ...
... Decimal Fractions , 197-199 199-202 · 202-206 206-209 209 209-213 213-215 • • 215-218 • • 218 219 220 221-224 224-227 Formation of Powers and Extraction of Roots , Any Root of a Decimal Fraction , Of Monomials - Of Polynomials ...
Side 121
... decimal places from the right hand . . Example 1. To extract the square root of 7 to within Having added four ciphers to the right hand of 7 , it becomes 70000 , whose root extracted to the nearest unit is 264 , which being divided by ...
... decimal places from the right hand . . Example 1. To extract the square root of 7 to within Having added four ciphers to the right hand of 7 , it becomes 70000 , whose root extracted to the nearest unit is 264 , which being divided by ...
Side 122
... decimals equal to the number of decimal places to be found in the root . Hence , to extract the square root of a decimal fraction : Annex ciphers to the proposed number until the decimal places shall be even , and equal to double the ...
... decimals equal to the number of decimal places to be found in the root . Hence , to extract the square root of a decimal fraction : Annex ciphers to the proposed number until the decimal places shall be even , and equal to double the ...
Side 123
... decimals : Change the vulgar fraction into a de- cimal and continue the division until the number of decimal places is double the number of places required in the root . root of the decimal by the last rule . Then extract the Ex . 1 ...
... decimals : Change the vulgar fraction into a de- cimal and continue the division until the number of decimal places is double the number of places required in the root . root of the decimal by the last rule . Then extract the Ex . 1 ...
Side 134
... decimal places , add 21 to this root , and divide the result by 4 . For another example , take 7√5 √11 + √3 and find the value of it to within 0,01 . We have , 7√5 √11 + √3 7√5 ( √11 - √3 ) 755-715 11-3 Now , 7√55 = √55 × 49 ...
... decimal places , add 21 to this root , and divide the result by 4 . For another example , take 7√5 √11 + √3 and find the value of it to within 0,01 . We have , 7√5 √11 + √3 7√5 ( √11 - √3 ) 755-715 11-3 Now , 7√55 = √55 × 49 ...
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Vanlige uttrykk og setninger
affected algebraic quantities arithmetical arranged binomial cents co-efficient common factor consequently contain continued fraction contrary signs cube root decimal deduce denominator denote divide dividend division entire number enunciation equa equal equation becomes equation involving example exponent expression extract the square figure Find the greatest find the values formula fourth fraction given number gives greater greatest common divisor greyhound Hence inequality irreducible fraction last term leaps least common multiple less letters logarithm manner monomial multiplicand multiplied negative nth root number of terms obtain operations perfect square positive roots preceding problem proposed equation proposed polynomials quotient radical reduced remainder result satisfy second degree second member second term square root substituted subtract suppose take the equation taken tens third tion transformation transposing unity unknown quantity verified whence whole number
Populære avsnitt
Side 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 148 - B, departed from different places at the same time, and travelled towards each other. On meeting, it appeared that A had travelled 18 miles more than B ; and that A could have gone B's journey in 15| days, but B would have been 28 days in performing A's journey. How far did each travel ? Ans.
Side 174 - It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference.
Side 28 - Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.
Side 183 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D ; and read, A is to B as C to D.
Side 112 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Side 190 - That is, the last term of a geometrical progression is equal to the first term multiplied by the ratio raised to a power whose exponent is one less than the number of terms.
Side 228 - Divide the first term of the remainder by three times the square of the root already found, and write the quotient for the next term of the root.
Side 92 - If A and B together can perform a piece of work in 8 days, A and c together in 9 days, and B and c in 10 days, how many days will it take each person to perform the same work alone.
Side 116 - ... brought down, there is no remainder, the proposed number is a perfect square. But if there is a remainder, you have only found the root of the greatest perfect square contained in the given number, or the entire part of the root sought. For example, if it were required to extract the square root of...