Stewart's specific subjects. Euclid. [1st] (-3rd stage). [With 2 issues of] Algebra |
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Resultat 1-5 av 15
Side 4
... centre of BCD , AC is equal to AB ; and because B is the centre of ACE , BC is equal to BA , but it has been proved that CA is equal to AB ; therefore CA , CB , are each of them equal to AB ; but things which are equal to the same are ...
... centre of BCD , AC is equal to AB ; and because B is the centre of ACE , BC is equal to BA , but it has been proved that CA is equal to AB ; therefore CA , CB , are each of them equal to AB ; but things which are equal to the same are ...
Side 3
... centre , distance from that centre . at any AXIOMS . I. Things equal to the same are equal to one another , II . If equals be added to equals , the wholes are equal . III . If equals be taken from equals , the remainders are equal . IV ...
... centre , distance from that centre . at any AXIOMS . I. Things equal to the same are equal to one another , II . If equals be added to equals , the wholes are equal . III . If equals be taken from equals , the remainders are equal . IV ...
Side 4
... centre of BCD , AC is equal to AB ; and because B is the centre of ACE , BC is equal to BA , but it has been proved that CA is equal to AB ; therefore CA , CB , are each of them equal to AB ; but things which are equal to the same are ...
... centre of BCD , AC is equal to AB ; and because B is the centre of ACE , BC is equal to BA , but it has been proved that CA is equal to AB ; therefore CA , CB , are each of them equal to AB ; but things which are equal to the same are ...
Side 5
... centre A , and at the distance AD , describe the circle DEF ; and because A is the centre of DEF , AE shall be equal to AD ; but C is likewise equal to AD ; whence AE and C are each of them equal to AD ; wherefore the straight line AE ...
... centre A , and at the distance AD , describe the circle DEF ; and because A is the centre of DEF , AE shall be equal to AD ; but C is likewise equal to AD ; whence AE and C are each of them equal to AD ; wherefore the straight line AE ...
Side 12
... centre C , at the distance CD , describe the circle EFG meeting AB in FG , and bisect FG in H , and join CF , CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . D G B Because ...
... centre C , at the distance CD , describe the circle EFG meeting AB in FG , and bisect FG in H , and join CF , CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . D G B Because ...
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Stewart's Specific Subjects. Euclid. [1st] (-3rd Stage). [With 2 Issues Of ... Stewart W and Co Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
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Populære avsnitt
Side 19 - If two triangles have two sides of the one equal to two sides of the...
Side 1 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a Right Angle; and the straight line which stands on the other is called a Perpendicular to it.
Side 8 - Upon the same base, and on the same side of it, there cannot be two triangles, that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity, equal to one another.
Side 16 - Any two sides of a triangle are together greater than the third side.
Side 12 - IF a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Side 5 - IF two angles of a triangle be equal to one another, the sides also which subtend, or are opposite to, the equal angles, shall be equal to one another.