Treatise on Trigonometry ...Macmillen & Company, 1889 - 504 sider |
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Resultat 1-5 av 40
Side xii
... roots 152 152-156 156 157-159 159-162 162-165 166 , 167 168-180 181 , 182 233-238 . Laws involving different bases and indices Extension of Index Notation § 2. Logarithmic Notation . 239 , 240 . 241-245 . Explanation of logarithms 246 ...
... roots 152 152-156 156 157-159 159-162 162-165 166 , 167 168-180 181 , 182 233-238 . Laws involving different bases and indices Extension of Index Notation § 2. Logarithmic Notation . 239 , 240 . 241-245 . Explanation of logarithms 246 ...
Side xvi
... roots 601 , 602 . Product of expressions of form cos a + i sin a 603-605 . De Moivre's Theorem · 606-609 . The qth roots of complex expressions 610-614 . Factorisations by solutions of equations . 416-418 418 , 419 419 , 420 420 , 421 ...
... roots 601 , 602 . Product of expressions of form cos a + i sin a 603-605 . De Moivre's Theorem · 606-609 . The qth roots of complex expressions 610-614 . Factorisations by solutions of equations . 416-418 418 , 419 419 , 420 420 , 421 ...
Side xvii
... roots of unity . 478 , 479 479 , 480 695-703 . Vector - quotients expressed as complex numbers 704-708 . Relation between two modes of interpreting i 481-485 485-487 • • MISCELLANEOUS EXAMPLES ANSWERS TO EXAMPLES 488-491 · 492-504 ...
... roots of unity . 478 , 479 479 , 480 695-703 . Vector - quotients expressed as complex numbers 704-708 . Relation between two modes of interpreting i 481-485 485-487 • • MISCELLANEOUS EXAMPLES ANSWERS TO EXAMPLES 488-491 · 492-504 ...
Side 95
... root , since 1 – cos2 C = sin2 C , 2ab sin C = √ { ( a + b + c ) ( a + b − c ) ( c + a − b ) ( b + c − a ) } . 151. To prove the half - angle formulæ . Since 1+ cos C = 2 cos2 C and 1 - cos C = 2 sin2 ¿ C , substituting in ( 1 ) and ...
... root , since 1 – cos2 C = sin2 C , 2ab sin C = √ { ( a + b + c ) ( a + b − c ) ( c + a − b ) ( b + c − a ) } . 151. To prove the half - angle formulæ . Since 1+ cos C = 2 cos2 C and 1 - cos C = 2 sin2 ¿ C , substituting in ( 1 ) and ...
Side 103
... root has to be taken must be positive . The conditions , geometrically considered , for a possible solution are that any length , any angle , and the ratio of any angle ( except the cos , tan , sec , or cot of such angles as may be ...
... root has to be taken must be positive . The conditions , geometrically considered , for a possible solution are that any length , any angle , and the ratio of any angle ( except the cos , tan , sec , or cot of such angles as may be ...
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acute angle algebraically angle AOB antiparallel base bisector bisects Brocard Brocard Circle Brocard Points centre chord circular measure circumcircle circumference circumradius convergent cos² cos³ cosec cosh cosine cot² cotangent decimal diameter difference directed length equal equation escribed circles Example expressed factors figure final line finite formulæ greater Hence hypothenuse inscribed integral last article Lemoine Circle logarithms magnitude middle point multiple negative nine-points circle obtuse opposite perp perpendicular positive PROP prove quadrant quantity radian radii radius ratios respectively revolver right-angled triangle S₁ sec² secant sector sides sin² sin³ sine sinh subtend subtraction tan-¹ tan² tangent theorem trigonometrical angle values zero
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