A Complete Treatise on Practical Mathematics: Including the Nature and Use of Mathematical Instruments: Logarithmic Tables, Trigonometry, Mensuration of Heights and Distances,--of Surfaces & Solids, Land Surveying, Gunnery, Gauging, Artificer's Measuring, Miscellaneous Exercises. With an Appendix on Algebra ... Principally Designed for the Use of Schools and AcademiesBell and Bradfute, 1792 - 431 sider |
Inni boken
Resultat 1-5 av 13
Side xi
... Segment of a Sphere , To find the Solidity of the middle Zone of a Sphere , To find the Area of a circular Spindle , To find the Solidity of a circular Spindle , To find the Solidity of the middle Zone of a circular Spin- dle , To find ...
... Segment of a Sphere , To find the Solidity of the middle Zone of a Sphere , To find the Area of a circular Spindle , To find the Solidity of a circular Spindle , To find the Solidity of the middle Zone of a circular Spin- dle , To find ...
Side 161
... for the area of the segment . The example being the fame as before , we have the versed fine equal 10 , and diameter 100 . 100 ) 10.0 ( .1 100 In the column of verfed fines find .1 And the I In MENSURATION OF SURFACES . 161 .
... for the area of the segment . The example being the fame as before , we have the versed fine equal 10 , and diameter 100 . 100 ) 10.0 ( .1 100 In the column of verfed fines find .1 And the I In MENSURATION OF SURFACES . 161 .
Side 162
... segment , whofe chord is 32 , the radius being 20 . Anf . 178.9168 . Ex . 5. Required the area of a fegment , its verfed fine being 31 , and diameter 50 yards . Anf . 54.1475 Sq . yards . PROBLEM XXIV . To find the area of the cycloid ...
... segment , whofe chord is 32 , the radius being 20 . Anf . 178.9168 . Ex . 5. Required the area of a fegment , its verfed fine being 31 , and diameter 50 yards . Anf . 54.1475 Sq . yards . PROBLEM XXIV . To find the area of the cycloid ...
Side 195
... segment , whose height is 8 inches , and the radius of its bafe 16 inches .. By RULE I. 16 AE 16 8 ) 256 32 = EF 8 = CE 40 = CF 3 120 treple prod . of diameter .. 64 fq . of the frust . height , 480 720 C & 2 7680 By RULE II . 7680 16 ...
... segment , whose height is 8 inches , and the radius of its bafe 16 inches .. By RULE I. 16 AE 16 8 ) 256 32 = EF 8 = CE 40 = CF 3 120 treple prod . of diameter .. 64 fq . of the frust . height , 480 720 C & 2 7680 By RULE II . 7680 16 ...
Side 216
... segment , whofe bafe is parallel to either of the axis . RULE . Divide the height of the fegment by that axe of the ellipfe of which it is a part , and find , in the table of circular fegments , an area , whofe verfed fine fhall be ...
... segment , whofe bafe is parallel to either of the axis . RULE . Divide the height of the fegment by that axe of the ellipfe of which it is a part , and find , in the table of circular fegments , an area , whofe verfed fine fhall be ...
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Vanlige uttrykk og setninger
abfciffa acres againſt alfo alſo altitude amplitude axis bafe baſe becauſe breadth centre chain chord of half circle circumference Co-fec Co-tan column cone conjugate cube defcribe dift diſtance divide divifor elevation Engliſh equal Euclid EXAMPLE fame fecond fegment fhall fimilar find the area find the folidity firſt fquare root fquare yards fruftum ftraight line fubtract fuch fuperficies furface girt given greateſt half the arch height horizontal houſe hypothenufe inftrument laft acquired velocity laſt lefs logarithm malt bufhels meaſure obferved off-fets oppofite ordinate parabolic perpendicular plane Plate quantity quotient rectangle Required the area Required the content Required the folidity rhombus right angles RULE Secant Secant Co-fec ſpace ſphere ſpindle ſquare ſteeple Suppofe tangent theodolite theſe thickneſs tranfverfe trapezium triangle triangular uſed verfed whofe diameter whofe fide whofe length whoſe wine gallons
Populære avsnitt
Side 27 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, etc.
Side 115 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 3 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 232 - E, is equal to twice as many right angles as the figure has sides, less four right angles.
Side 1 - ... common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, each to each ; and the base EA is equal to the base EB ; (i.
Side 38 - BG; that is, the fum of the fides is to their difference, as the tangent of half the fum of the angles at the bafe to the tangent of half their difference.
Side 372 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained...
Side 38 - AB the greater side for a distance, let a circle be described, meeting AC, produced in E, F, and BC in D; join DA, EB, FB; and draw FG parallel to BC, meeting EB in G. The angle EAB (32.
Side 38 - ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together ; therefore FAD is the difference of the angles at the...
Side 395 - TO divide a given ftraight line into two parts, fo that the rectangle contained by the whale, and one of the parts, fhall be equal to the fquare of the other part. Let AB be the given ftraight line; it is required to divide it into two parts, fo that the rectangle contained by the whole, and one of the parts, fhall be equal to the fquare of the other part. Upon AB...